1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crazy boy [7]
4 years ago
11

How to determine if a linear system is consistent or inconsistent?

Mathematics
1 answer:
NNADVOKAT [17]4 years ago
6 0
I just want the points


tysm!

:)
You might be interested in
1. La asistencia a un juego de béisbol profesional fue de 4500 personas y el dinero
Elena-2011 [213]

Resolviendo un sistema de ecuaciones veremos que se vendieron 900 boletos de $15 y 3600 boletos de $10.

<h3> ¿Cuántos boletos de cada tipo se vendieron?</h3>

Primero definamos las variables:

  • x = número de bolteos de $10 vendidos.
  • y = número de bolteos de $15 vendidos.

Sabemos que se vendieron 4500 boletos, entonces:

x + y = 4500

Y se recaudo un total de $49,500, entonces:

x*$10 + y*$15 = $49,500

Entonces tenemos un sistema de ecuaciones:

Para resolver esto, primero debemos aislar una de las variables en la primer ecuación, voy a aislar x:

x = 4500 - y

Ahora reemplazamos esto en la otra ecuación:

(4,500 - y)*$10 + y*$15 = $49,500

Ahora debemos resolver estoy para y.

$45,000 - y*$10 + y*$15 = $49,500

y*$5 = $49,500 - $45,000 = $4,500

y = ( $4,500)/$5 = 900

Entonces:

x = 4500 - 900 = 3600

Se vendieron 900 boletos de $15 y 3600 boletos de $10.

Sí quieres aprender más sobre sistemas de ecuaciones:

brainly.com/question/13729904

#SPJ1

3 0
2 years ago
With water from one hose, a swimming pool can be filled in 9 hours. A second, larger hose used alone can fill the pool in 2 hour
Monica [59]

1/9 + 1/2 = 1/x

Let x = length of time it will take both hoses to work together

Multiply both sides by 18x.

2x + 9x = 18

10x = 18

x = 18/10

x = 9/5

x = 1.8 hours

In other words, if both hoses work together, the pool can be filled in 1 hour and 48 minutes.

5 0
3 years ago
Find the solution of given expression <br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B6%20%5Ctimes%20216%7D%20" id="TexFo
Morgarella [4.7K]
6x216 multiply them and u get 1296 then calculate the square root and your answer is 36
5 0
3 years ago
Read 2 more answers
26. Law of sines, please give a step by step explanation
Stels [109]

Answer:

  174.6 ft

Step-by-step explanation:

It can be helpful to draw a diagram of the triangle we're concerned with. (See attached.)

We know the angle at the end of the shadow inside the triangle is 52°-22° = 30°. We assume the tree is growing straight up out of the hillside, so its angle with the hill inside the triangle is 90°+22° = 112°. Then the remaining angle between the shadow and the tree at the top of the tree is ...

  180° -30° -112° = 38°

Now, we have the angle opposite the tree, and the angle opposite the known side length of the triangle (215 feet along the hill, AC in the diagram). This is enough information to usefully use the Law of Sines.

  c/sin(C) = a/sin(A)

  c = a(sin(C)/sin(A)) = (215 ft)(sin(30°)/sin(38°)) ≈ 174.6 ft

The height of the tree is about 174.6 feet.

5 0
3 years ago
Complete each ratio table
Nesterboy [21]
?????????? is there supposed to be an attachment because its not there.
5 0
3 years ago
Other questions:
  • Logaritnm<br> 3 log b + 2 log d
    13·1 answer
  • 0.09502 to 2 decimal places
    12·1 answer
  • I need help on 9 thxs
    11·1 answer
  • What is the inverse of the function f(x) = 4x + 8?
    5·1 answer
  • Which equation is equivalent to 3 (5x – 4) = 2 (7x)? A. 5x - 4 = 142
    11·1 answer
  • Fill in missing information to make the equality true: <br> (... +2a)2 = … +12ab2+4a2.
    13·1 answer
  • Pls help me in this question
    10·1 answer
  • Please help 20 points
    5·2 answers
  • Which of the following are possible side lengths for a triangle
    13·1 answer
  • How do i write improper fractions as mixed numbers?<br> Explain with examples
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!