The sum of the two hamsters weight = 1950g
If hamster1 (x) = hamster2 (y) + 300g
Therefore
1950g = x + y
1950g = x + (x +300g)
1950g - 300g = x + x
1650g = 2x
825g = x
Therefore
Hamster1 = x = 825g
Hamster2 = x + 300g = 1125g
Answer:
(x+2)(x+1)=0
so x = -2,-1
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
1. You have the following parent function given in the problem above:
2. And you have the function 
3. By definition, if you have the function 
and 
it is a vertical stretch.
4. Therefore, you have that:
Therefore the answer is: It is a vertical stretch.
The answer would be the first one, (measure 1 is equal to 1/2(SP + QR)). You would just use the formula for intercepted arcs.
<h2>
Answer:</h2><h2>
The probability that Roy gives randomly an SUV = 15 / 47</h2>
Step-by-step explanation:
The total number of used cars owned by Roy = 47
[12 trucks + 20 cars + 15 SUV = 47 cars]
The total number in sample space, n (S) = 47
The probability that Roy is giving away and SUV = ?
Let A be the event that Roy is giving an SUV
Total no of SUV's , n (A) = 15
The probability of giving an SUV, P (A) = n (A) / n (S)
P (A) = 15 / 47
