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MakcuM [25]
3 years ago
12

Plz help this was due yesterday butttttt i didn’t want to do it...

Chemistry
2 answers:
sergejj [24]3 years ago
8 0
So what am I suppose to answer here?
8_murik_8 [283]3 years ago
7 0

Answer:

I don't get what you want me to do cause n Explano questions showing ation:

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What is the chemical formula of diphosphorus monoxide?
Daniel [21]

Answer:

The chemical formula of diphosphorus monoxide is OP2.

I'm not sure if this is correct, but hope it helps! :)

7 0
3 years ago
When a ketone and its enol are in equilibrium, under most conditions the concentration of the enol is __________ the concentrati
Ray Of Light [21]

Answer:

D). Much lower than  

Explanation:

When a ketone and its enol are in equilibrium, under most conditions the concentration of the enol is <u>Much lower than</u> the concentration of the ketone

because :

Carbon- oxygen bond is more stable(stronger) than Carbon-Carbon Bond

Keto - enol tautomerism is :

H -C-C=O \rightleftharpoons C=C-O-H

Ketone has C=O and enol has C=C

C=O bond energy is 745 kJ/mol

C=C bond energy is 614 kJ/mol

5 0
3 years ago
Give an example of a polar molecular compound that dissolves in water
VLD [36.1K]
Try sugar. I hope this helps!!!!!
7 0
4 years ago
How many elements are found in 2CuSO4?<br> A.5<br> B.4<br> C.2<br> D.3
Aneli [31]

Answer:

d

Explanation:

the reason is you have Cu S and O

4 0
3 years ago
Devise a temperature scale, abbreviated g, for which the magnitude of the ideal gas constant is 1.00 j g–1 mol–1 .
melisa1 [442]

The value of ideal gas constant (R) in Joule is 8.314 Joule Kelvin^{-1}mol^{-1}. Now the given expression is 1.00 J. gg^{-1}.mole^{-1}. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin  = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C  = (-) \frac{8.314}{272.15}=0.030g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.  

7 0
4 years ago
Read 2 more answers
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