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ahrayia [7]2 years ago

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Suppose you need to prepare 141.9 mL of a 0.223 M aqueous solution of NaCl. What mass of NaCl do you need to use to make the sol

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The computation of the mass need to use to make the solution is shown below:

We know that molarity is

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So,

$Number\ of\ moles = Molarity\ \times Volume\ in\ L$

$= 0.223\times 0.141$

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The Molecular weight of NaCl is 58.44 g/mole

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