1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ivanzaharov [21]
2 years ago
5

What coefficients must be added to balance the following equation?_____NaOH + _____H2 SO4 _____ Na2SO4 + _____ H2O 2, 1, 1, 13,

1, 1, 32, 1, 1, 24, 2, 2, 1 ...?
Chemistry
2 answers:
alexgriva [62]2 years ago
7 0

_____NaOH + _____H2 SO4 _____ Na2SO4 + _____ H2O ,

To balance this equation,

Step 1:

Balance the number of sodium on both side:

by multiplying the NaOH by 2 that is:

2NaOH+H2SO4-------->Na2SO4+H2O

Step2:

As NOW the number of oxygen atom and hydrogen atom are not equal on both sides. So we multiply this H2O by 2 that is:

2NaOH+H2SO4-------->Na2SO4+2H2O

Now the no of all atoms on product side is equal to no of all atoms in the reactant side.

so the coefficient is 2 NaOH+1 H2SO4-------->1 Na2SO4+2 H2O.

kaheart [24]2 years ago
4 0
2NaOH+1H2SO4→1Na2SO4+2H2O
hope it will help you
You might be interested in
A power plant is driven by the combustion of a complex fossil fuel having the formula C11H7S. Assume the air supply is composed
AlekseyPX

(a) 4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 20.68N_2;

(b) 4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2;

(c) 23 900 kg air; (d) air:fuel = 10.2; (e) air:fuel = 12.2:1

(a) <em>Balanced equation including N_2 from air</em>  

The balanced equation <em>ignoring</em> N_2 from air is  

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2  

Moles of N_2 =55 mol O_2 × (3.76 mol N_2/1 mol O_2) = 206.8 mol N_2  

<em>Including</em> N_2 from air, the balanced equation is  

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 206.8N_2  

(b) <em>Balanced equation for 120 % stoichiometric combustion</em>  

Moles of O_2 = 55 mol O_2 × 1.20 = 66.00 mol O_2  

Excess moles O_2 = (66.00 – 55) mol O_2 = 11.00 mol O_2  

Moles of N_2 = 66.00 mol O_2 × (3.76 mol N_2/1 mol O_2) = 248.2 mol N_2  

The balanced equation is

4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2

(c) <em>Minimum mass of air</em>  

Moles of O_2 required = 1700 kg C_11 H_7S

× (1 kmol C_11 H_7S/185.24 kg C_11 H_7S) × (55 kmol O_2/4 kmol C_11 H_7S)

= 126.2 kmol O_2  

Mass of O_2 = 126.2 kmol O_2 × (32.00 kg O_2/1 kmol O_2) = 4038 kg O_2  

Mass of N_2 required = 126.2 kmol O_2 × (3.76 kmol N_2/1 kmol O_2)

× (28.01 kg N_2/1 kmol N_2) = 13 285 kg N_2  

Mass of air = Mass of N_2 + mass of O_2 = (4038 + 13 285) kg = 17 300 kg air  

(d) <em>Air:fuel mass ratio for 100 % combustion</em>  

Air:fuel = 17 300 kg/1700 kg = <em>10.2 :1 </em>

(e) <em>Air:fuel mass ratio for 120 % combustion </em>

Mass of air = 17 300 kg × 1.20 = 20 760 kg air  

Air:fuel = 20 760 kg/1700 kg = 12.2 :1  

6 0
2 years ago
Which of the following ratios are needed to determine the mass of oxygen produced from the decomposition of 10 grams of potassiu
Zielflug [23.3K]

The ratios which are needed to determine the mass of oxygen produced from the decomposition of 10 grams of potassium chlorate are;

  • 31.998 g O2 : 1 mole O2
  • 3 mole O2 : 2 mole KClO3
  • 112.55 g KClO31 mole KClO3

From stoichiometry;

  • We can conclude that according to the reaction;

3 moles of oxygen requires 2 moles of KClO3 to be produced.

And from molar mass analysis;

  • 31.998 g O2 is equivalent to 1 mole O2
  • O2112.55 g KClO3 is equivalent to 1 mole KClO3

Read more:

brainly.com/question/9920155

7 0
2 years ago
Does anyone know how to do this???​
Lelechka [254]

Answer:

2.9 g/cm³

Explanation:

From the question given above, the following data were obtained:

Mass = 236.376 g

Volume = 81.5 cm³

Density =?

Density can be defined as the mass of a substance per unit volume of the substance. It can be expressed mathematically as:

Density = mass /volume

With the above formula, we can obtain the density of the object as shown below:

Mass = 236.376 g

Volume = 81.5 cm³

Density =?

Density = mass /volume

Density = 236.376 / 81.5

Density = 2.9 g/cm³

Thus, the density of the object is 2.9 g/cm³

8 0
3 years ago
Is condensation a chemical or a physical change?​
Step2247 [10]

Answer:

physical change

Explanation:

8 0
2 years ago
Read 2 more answers
You want to know if iron will rust faster at higher temperatures you conduct a series of experiments under different conditions
Dafna1 [17]
You would then conduct a theory
4 0
3 years ago
Read 2 more answers
Other questions:
  • A solution with a pH of 6 has a ______ difference in H ion concentration than a solution with pH of 10.
    5·1 answer
  • a teacher uses a bow and arrow to demonstrate accuracy and precision. she shoots several arrows, aiming at the exact center of t
    7·1 answer
  • The scientific method is a strict of steps that are always followed in the same order true or false
    12·2 answers
  • Select the correct answer. Which property is typical of a covalent compound?
    7·2 answers
  • In an electron dot diagram of propane (C3H8), how many double bonds are present?
    8·2 answers
  • For which of the following processes will \DeltaΔS be negative?PbCl2(s) = Pb2+(aq) + 2 Cl-(aq)MgO(s) + CO2(g) = MgCO3(s)CO2(aq)
    7·1 answer
  • A rock that has a mass if 180 grams dropped in a graduated cylinder that was originally filled to 52ml; it now reads 62ml. What
    13·1 answer
  • What best describes the location of an atom's electrons? (1 point)
    15·1 answer
  • Pls hurrry<br>what are greenhouse effect 1 paragraph and come friends
    8·1 answer
  • Unit: Stoichiometry
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!