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Oliga [24]
1 year ago
8

Give the hybridization for the br in bro4⁻.

Chemistry
1 answer:
elixir [45]1 year ago
8 0

The hybridization for the Br in BrO4⁻ is sp^{3}. So, the correct option is (e).

In chemistry, the idea of combining atomic orbitals to create new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) is known as orbital hybridisation (or hybridization). These new hybrid orbitals are suitable for the pairing of electrons to form chemical bonds in valence bond theory.

Because more directional hybridised orbitals result in higher overlap when creating bonds, stronger bonds are formed, which favours the hybridization of orbitals. When hybridization takes place, this leads to more stable molecules.

One s orbital and three p orbitals combine to form four sp^{3} orbitals, each of which has a 25% s character and a 75% p character. This process is known as sp^{3} hybridization. Anytime an atom is surrounded by four groups of electrons, this kind of hybridization is necessary.

Learn more about hybridization here:

brainly.com/question/12207339

#SPJ4

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What is the value of the activation energy of the uncatalyzed reaction? Express your answer to three significant figures and inc
goblinko [34]

Answer:

175 kJ

Explanation:

Activation energy can be defined as the potential energy that is needed to change reactants to products. This is the minimum energy required for the chemical reaction to take place. Thus, using the given figure:

Activation energy = activation complex - reactant energy

In the given figure, activation complex = 400 kJ

reactant energy = 225 kJ

Therefore:

Activation energy = 400 - 225 = 175 kJ

3 0
3 years ago
Read 2 more answers
Calculate the energy required to ionize a hydrogen atom to an excited state where the electron is initially in the n = 5 energy
SVETLANKA909090 [29]

. The energy of shells in a hydrogen atom is calculated by the formula E = -Eo/n^2 where n is any integer, and Eo = 2.179X10^-18 J. So, the energy of a ground state electron in hydrogen is:

E = -2.179X10^-18 J / 1^2 = -2.179X10^-21 kJ

Consequently, to ionize this electron would require the input of 2.179X10^-21 kJ


2. The wavelength of a photon with this energy would be:

Energy = hc/wavelength

wavelength = hc/energy

wavelength = 6.626X10^-34 Js (2.998X10^8 m/s) / 2.179X10^-18 J = 9.116X10^-8 m

Converting to nanometers gives: 91.16 nm


3. Repeat the calculation in 1, but using n=5.


4. Repeat the calculation in 2 using the energy calculated in 3.

7 0
3 years ago
Read 2 more answers
Find the number of CoCl2 units present in a 0.78 mol sample.
stich3 [128]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

1 mole of \sf{ COCl_2} has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of \sf{COCl_2} will have ~

\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}

\qquad \sf  \dashrightarrow \:  \approx4.7 \times 10 {}^{23}  \:  \:  \: molecules

5 0
2 years ago
Natasha and Reanna observe a large airplane in the troposphere. Which experimental setup below would best determine how changing
snow_lady [41]

Answer:

i am pretty sure the answer is a

Explanation: because the airplane's flight time has to be the independent variable for it to affect the dependent variable that is the speed of how fast the airplane is going.

8 0
3 years ago
Read 2 more answers
372 mL is the volume of Aluminum, density is 2.70 g/mL what is the mass in grams
podryga [215]

Answer:

930 g

Explanation:

D = m/V     Multiply both sides by V

m = VD

<em>Data: </em>

V = 372 cm³

D = 2.70 g/cm³

<em>Calculation: </em>

m = 372 × 2.50

m = 930 g

The mass of Al is 930 g.

7 0
3 years ago
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