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11 months ago

Give the hybridization for the br in bro4⁻.

Chemistry

1 answer:

elixir [45]11 months ago

8 0

The hybridization for the Br in BrO4⁻ is $sp^{3}$ . So, the correct option is (e).

In chemistry, the idea of combining atomic orbitals to create new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) is known as orbital hybridisation (or hybridization). These new hybrid orbitals are suitable for the pairing of electrons to form chemical bonds in valence bond theory.

Because more directional hybridised orbitals result in higher overlap when creating bonds, stronger bonds are formed, which favours the hybridization of orbitals. When hybridization takes place, this leads to more stable molecules.

One s orbital and three p orbitals combine to form four $sp^{3}$ orbitals, each of which has a 25% s character and a 75% p character. This process is known as $sp^{3}$ hybridization. Anytime an atom is surrounded by four groups of electrons, this kind of hybridization is necessary.

Learn more about hybridization here:

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A is often written as an if/then statement. O prediction O law O theory O guess

frosja888 [35]

The answer is theory because it says if and that means theory

3 0

2 years ago

How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f

BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

$A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}$

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

$A=\text{ 50 }\times2^{\frac{-t}{14.3}}$

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

$\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}$

So, after 84 days the P-32 remaining will be 0.85 mg

4 0

6 months ago

A 10.21 mol sample of argon gas is maintained in a 0.7564 L container at 296.9 K. What is the pressure in atm calculated using t

soldi70 [24.7K]

Answer:

The pressure in atm calculated using the van der Waals' equation, is 337.2atm

Explanation:

This is the Van der Waals equation for real gases:

(P + a/v² ) ( v-b) = R .T

where P is pressure

v is Volume/mol

R is the gas constant and T, T° in K

a y b are constant for each gas, so those values are data, from the statement.

[P + 1.345 L²atm/mol² / (0.7564L/10.21mol)² ] (0.7564L/10.21mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K

[P + 1.345 L²atm/mol² / 5.48X10⁻³ L²/mol²] (0.074 L/mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K

(P + 245.05 atm) (0.04181L/mol) = 0.082 L.atm/mol.K . 296.9K

(P + 245.05 atm) (0.04181L/mol) = 24.34 L.atm/mol

0.04181L/mol .P + 10.24 L.atm/mol = 24.34 L.atm/mol

0.04181L/mol .P = 24.34 L.atm/mol - 10.24 L.atm/mol

0.04181L/mol. P = 14.1 L.atm/mol

P = 14.1 L.atm/mol / 0.04181 mol/L

P = 337.2 atm

4 0

2 years ago

3. Gasoline, coal, batteries, and logs all have chemical energy. When they burn that chemical energy will be transformed into en

Arturiano [62]

Answer:

Thermal energy

Explanation:

When gasoline, coal, batteries and logs are all burn they transform chemical energy to thermal energy.

The chemical energy is the energy held between chemical chains and bonds within an atom.

When they combust, they release thermal energy
Chemical energy is a potential energy.
The thermal energy is a kinetic energy
It increase the average motion of the particles in the medium
The breaking bond when produces heat which is a form of thermal energy.

3 0

2 years ago

Describe how you might prepare disodium phosphate given a solution of phosphoric acid, 0.500 molar and a solution of sodium hydr

PilotLPTM [1.2K]

Explanation:

When 2 moles of sodium hydroxide (NaOH) reacts with 1 mole of phosphoric acid (H3PO4) it gives 1 moles disodium phosphate Na2HPO4 and 2 moles of water.

0.5 molar solution indicates half moles of molecules are present in per ltr solution.

to prepare disodium phosphate you need to dilute phosphoric acid solution to 0.25 molar and add equal quantity of 0.5 molar solution.

$2 NaOH + H_3PO_4 \: \rightarrow \: Na_2HPO_4 + 2 H_2O$

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8 0

1 year ago