Answer: The U.S. has a greater gold resource
Explanation: Canada has 3,500 tons while the U.S. has 6,000
"Asthenosphere" describes a section of Earth's structure below moving continents as parts of large plates.
Answer: Option C
<u>Explanation:
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The asthenosphere denoted as the upper mantle of a very sticky, mechanically weak and flexible area in the earth. It is located below the surface of the lithosphere at depths of about 80 and 200 km (in terms of miles, 50 and 120). The boundary is commonly called the lithospheric LAB - asthenosphere.
The asthenosphere is nearly solid, though some of its regions could be molten below mid-ocean ridges for an instance. The lower asthenosphere boundary isn't well defined. The asthenosphere's thickness depends primarily on the temperature.
Balanced chemical equation is - 3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O
Fe2+ + NO3- + H+ → Fe3+ + NO3- + NO + H2O
Fe+22+ + N+5O-23- + H+1+ → Fe+33+ + N+5O-23- + N+2O-2 + H+12O
3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O
A balanced chemical equation specifies the quantities of reactants and products required to meet the Law of Conservation of Mass. This signifies that there is the same number of each sort of atom on the left side of the equation as there are on the right side. The rule of a balanced chemical equation is used to determine if two weights put on opposing sides of the fulcrum will balance each other.
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Answer:
In 4.5 grams of tetraphosphorus decoxide we have 3.85 * 10^22 phosphorus atoms
Explanation:
Step 1: Data given
tetraphosphorus decoxide = P4O10
Molar mass of P4O10 = 283.89 g/mol
Mass of P4O10 = 4.5 grams
Number of Avogadro = 6.022 * 10^23 / mol
Step 2: Calculate moles of P4O10
Moles P4O10 = mass P4O10 / molar mass P4O10
Moles P4O10 = 4.5 grams / 283.89 g/mol
Moles = 0.016 moles
Step 3: Calculate moles of P
For 1 mol P4O10 we have 4 moles of phosphorus
For 0.016 moles P4O10 we have 4*0.016 = 0.064 moles P
Step 4: Calculate number of P atoms
Number of P atoms = moles P * number of Avogadro
Number of P atoms = 0.064 moles * 6.022*10^23
Number of P atoms = 3.85 * 10^22 atoms
In 4.5 grams of tetraphosphorus decoxide we have 3.85 * 10^22 phosphorus atoms
1.25 g x 22.4 l / 1 mol = 28 g/mol
