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Bas_tet [7]
3 years ago
15

Which option is an example of a chemical change?

Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
6 0
Firework exploding. Thank you :)
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Imagine you are stranded in
jenyasd209 [6]

Explanation:

1st if you think you going to a place where you can be in situation where no one can help so you shouldn't go

2nd even somehow you reached these place you should try to make a shelter.

3rd use your hand warmer.

4th don't loose hope and have a positive thinking about yourself

5th if your hungry so be like bear Grylls eat anything that safe for your health.

6th at last if you find a helicopter so try to burn wood and make smoke as much as possible.

hope this helps you

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5 0
2 years ago
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What is the definition of law of chemical combination??
Jet001 [13]

Answer:

In simple terms, this law states that matter can neither be created nor destroyed. In other words, the total mass, that is, the sum of mass of reacting mixture and the products formed remains constant.

HOPE IT'S HELPFUL!

8 0
3 years ago
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All animals need oxygen gas (O2) for their primary cellular-level functioning. Inside the cell, O2 is split apart into oxygen at
il63 [147K]

Answer:

H₂O (water)

Explanation:

The reaction given is the glucose combustion inside the cells. During the combustion, it will be formed carbonic gas, water and energy.

The oxygen molecule is split in their two atoms of O. The element which has 1 proton and 1 electron is the hydrogen (H). So, when hydrogen reacts with oxygen, they form water (H₂O).

6 0
3 years ago
What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, an
Mandarinka [93]

Answer: The empirical formula of the compound is Fe_1S_1O_4

Explanation:

Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.

Percentage of iron in a compound = 36.76 %

Percentage of sulfur in a compound = 21.11 %

Percentage of oxygen in a compound = 42.13 %

Consider in 100 g of the compound:

Mass of iron in 100 g of compound = 36.76 g

Mass of iron in 100 g of compound = 21.11 g

Mass of iron in 100 g of compound = 42.13 g

Now calculate the number of moles each element:

Moles of iron=\frac{36.76 g}{55.84 g/mol}=0.658 mol

Moles of sulfur=\frac{21.11 g}{32.06 g/mol}=0.658 mol

Moles of oxygen=\frac{42.13 g}{16 g/mol}=2.633 mol

Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other

For Iron element = \frac{0.658 mol}{0.658 mol}=1

For sulfur element = \frac{0.658 mol}{0.658 mol}=1

For oxygen element = \frac{2.633 mol}{0.658 mol}=4.001\approx 4

So, the empirical formula of the compound is Fe_1S_1O_4

4 0
3 years ago
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Which is true for a substance that releases energy?
Ksivusya [100]

Answer:

e is the answer for the question

5 0
4 years ago
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