AB = 6 cm, AC = 12 cm, CD = ?
In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.
Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°
In order to find ∠BCA, use the law of sines:
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA
Now add ∠BCA (30°) to ∠DCB = 35° to find ∠DCA.
∠DCA = 30 + 35 = 65°
Since triangle DCA has 180°, we know ∠CAD = 180 - ∠DCA - ∠ADC = 180 - 65 - 55 = 60°
In triangle DCA we now have all three angles and one side, so we can use the law of sines to find the length of DC.
12cm/sin(∠ADC) = DC/sin(∠DCA)
12cm/sin(55°) = DC/sin(60°)
DC = 12cm*sin(60°)/sin(55°)
DC = 12.686 cm
Answer:
A (50)
Step-by-step explanation:
Mean is the total numbers added up divided by the # of numbers.
There are 6 numbers.
51 + 60 + 80 + 32 + 47 + 30 = 300
300/6 = 50
Therefore, the answer is A.
An equation that goes through (-2, 1) and has a slope of 4 is y = 4x + 9.
You can find this by looking for the y-intercept (b) by using the slope (m), the point and slope intercept form. The work is below for you.
y = mx + b
1 = 4(-2) + b
1 = -8 + b
9 = b
Now we can use that and the slope to create the equation y = 4x + 9
1)
A has a greater principal
2)
Principal of A is $500, the principal of B is $400, so A's principal is greater by $100
3)
Annual interest rate of A:
10/500 x 100
interest rate of A = 2%
The interest rate of B is higher.
4)
B's annual interest rate is 5% and A's annual interest rate is 2%, so B's is higher by 3%.
Jiri is 22 years old and Pamela is 66
22•3=66
22+66=88
