Two positive integers have a sum of 17 and a product of 66. what are the integers?

Darina [25.2K]

2 x 2 x 2 x 3

Because you are multiplying two, four times

6 0

3 years ago

Suppose that 75% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou

RSB [31]

Answer:

b) 0.2961

c) 0.2251

d) Mean = 11.25, Standard deviation = 1.667

Step-by-step explanation:

We are given the following information:

We treat trucks undergoing a brake inspection passin as a success.

P( trucks undergoing a brake inspection passes the test) = 75% = 0.75

a) Conditions for binomial probability distribution

There are n independent trial.
Each trial have a success probability p
The probability of success is same for all trials.

Then the number of trucks undergoing a brake inspection follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15

b) P(proportion of groups will between 8 and 10 trucks pass the inspection)

We have to evaluate:

$P(8\leq x \leq 10) = P(x = 8) + P(x = 9) + P(x = 10)\\= \binom{15}{8}(0.75)^8(1-0.75)^7 + \binom{15}{9}(0.75)^9(1-0.75)^6 + \binom{15}{10}(0.75)^{10}(1-0.75)^5\\= 0.0393 + 0.0917 + 0.1651\\= 0.2961$

c) P( exactly 3 trucks fail the inspection)

p = 0.25

$P(x = 3)\\= \binom{15}{3}(0.25)^3(1-0.25)^{12}\\=0.2251$

d) Mean and standard deviation

$\mu = np = 15(0.75) = 11.25\\\sigma = \sqrt{np(1-p)} = \sqrt{15(0.75)(1-0.75)} = 1.667$

6 0

3 years ago

How many arrangements can be made using 2 letters of the word HYPERBOLAS if no letter is to be used more than once?

alisha [4.7K]

Answer:

90 arrangements

Step-by-step explanation:

Since there are no repititions of letters, there are unique 10 letters in total.

THe number of arrangements would be 2 permutation 10. We need the formula for permutation. That is:

$nPr=\frac{n!}{(n-r)!}\\$

Now, n = 10 [total] and r is 2, so we have:

$nPr=\frac{n!}{(n-r)!}\\\\_{10}P_{2}=\frac{10!}{(10-2)!}\\=\frac{10!}{8!}\\=\frac{10*9*8!}{8!}\\=10*9\\=90$

So, there can be 90 arrangements

3 0

3 years ago

40 points and brainliest get it before it gets claimed.

denis23 [38]

Answer:

yuh

Step-by-step explanation:

4 0

3 years ago

Writing an equation and drawing its graph to model a real-world situation

Mariana [72]

Answer:

A = B + 15

Step-by-step explanation:

Let Diane sold B books in one hour,

Additional earning by selling 1 book = 1$

Additional earning by selling B books = Number of books sold × Additional earning by selling one book

= B × ($1.00)

= $B

Fixed earning of Diane in one hour of part time = $15

Total earnings = B + 15

A = B + 15

Table to find the input-output values for the graph,

A 15 16 17 18

B 0 1 2 3

Now we can plot the points on the graph.

7 0

3 years ago