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IgorLugansk [536]
3 years ago
9

The low temperature last week was 13 Fahrenheit (F). What was the low temperature last week in degrees Celsius (C)? [C =59(F 32)

]
Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0

Answer:

The low temperature last week was of -10ºC.

Step-by-step explanation:

The relation between temperatures in celsius(C) and Fahrenheit(F) is given by the following equation:

F = \frac{9C}{5} + 32

Here, we have that F = 13, and we want to find C. So

13 = \frac{9C}{5} + 32

\frac{9C}{5} = -19

9C = -90

C = - \frac{90}{9}

C = -10

The low temperature last week was of -10ºC.

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The product of a non-zero rational number and an irrational number is irrational.

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105-30-45-3028+10000000000000038492=?
Volgvan

Answer:

105-30-45-3028+10000000000000038492= 1.000000000000003e19

Step-by-step explanation:

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8 0
3 years ago
150 decreased by 60%
kodGreya [7K]
Hello there the answer to your question would be 60. Since 150-(60%*150) = 150 - 60 *150 = (1-60%)*150 = (100%-60%) * 150= 40% * 150 = 40/100 * 150 = 40 * 150 ÷ 100 = 6000/100 = 60. Hope this helps you out, have a great day!
8 0
3 years ago
The time taken to assemble a laptop computer in a certain plant is a random variable having a normal distribution of 20 hours an
ludmilkaskok [199]

Answer:

a) 40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.

b) 34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 20, \sigma = 2

a)Less than 19.5 hours?

This is the pvalue of Z when X = 19.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{19.5 - 20}{2}

Z = -0.25

Z = -0.25 has a pvalue of 0.4013.

40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.

b)Between 20 hours and 22 hours?

This is the pvalue of Z when X = 22 subtracted by the pvalue of Z when X = 20. So

X = 22

Z = \frac{X - \mu}{\sigma}

Z = \frac{22 - 20}{2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 20

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 20}{2}

Z = 0

Z = 0 has a pvalue of 0.5

0.8413 - 0.5 = 0.3413

34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.

4 0
3 years ago
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