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Rina8888 [55]
3 years ago
13

In an experiment, six people are different places around the earth drop an apple at the same time. Which apple will fall to the

earth? A. Only apple U and Z will fall to the earth B. all of the apples will fall to the earth. C. only apple U will fall to the earth D. only apples U,V,Y and Z will fall to the earth

Chemistry
1 answer:
Natali5045456 [20]3 years ago
5 0

Hello there

the answer is B. All the apples will fall to the earth

thank you

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What type of chemical bond is present in the cl2 molecule?.
nikklg [1K]

Answer:

Covalent Bond

Explanation:

A covalent Bond because each one P electron fills the place of the last P orbital.

Hope this helps!!  Mark brainiest please :)

4 0
3 years ago
Roger has a car that accelerates at 5 m/s2. If the car has a mass 0f 1000 kg, how much force does the car produce?
jarptica [38.1K]

Answer:

<h2>The answer is 5000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1000 × 5

We have the final answer as

<h3>5000 N</h3>

Hope this helps you

6 0
3 years ago
Read 2 more answers
Write a balanced equation to show the reaction of gaseous ethane with gaseous oxygen to form carbon monoxide gas and water vapor
Korolek [52]
<span>2 C2H6(g) + 5 O2(g) --------> 4 CO(g) + 6 H2O(g)

</span>
7 0
4 years ago
Calculate the ratio of the velocity of helium atoms to the velocity of neon atoms at the same temperature.
o-na [289]

Answer:

vHe / vNe = 2.24

Explanation:

To obtain the velocity of an ideal gas you must use the formula:

v = √3RT / √M

Where R is gas constant (8.314 kgm²/s²molK); T is temperature and M is molar mass of the gas (4x10⁻³kg/mol for helium and 20,18x10⁻³ kg/mol for neon). Thus:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

The ratio is:

vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol

<em>vHe / vNe = 2.24</em>

<em />

I hope it helps!

8 0
3 years ago
The vapor pressure of pure water at 250C is 23.77 torr. What is the vapor pressure of water above a solution that is 1.500 m glu
Olegator [25]

Answer:

Vapor pressure of water = 23.14torr

Explanation:

When you made a solution, vapor pressure decreases following Raoult's law:

P_{solution} = X_{solvent} P_{solvent}

<em>Where P is vapor pressure and X mole fraction</em>

As vapor pressure of water is 23.77torr we must find the mole fraction of water knowing the solution is 1.500m glucose (That is 1.500 moles of glucose per kg of water = 1000g of water).

1000g of H₂O are, in moles (Molar mass: 18.02g/mol):

1000g H₂O ₓ (1mole / 18.02g) = 55.5 moles of H₂O.

As we know now the solution contains 55.5 moles of water and 1.5 moles of glucose. Thus, mole fraction of water (Solvent) is:

X_{H_2O} = \frac{55.5molesH_2O}{55.5molesH_2O + 1.5 molesGlucose} = 0.9737

Replacing in Raoult's law, pressure of water above the solution is:

P_{solution} = X_{solvent} P_{solvent}

P_{solution} = 0.9737*23.77torr

<h3>Vapor pressure of water = 23.14torr</h3>
7 0
4 years ago
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