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Bad White [126]
3 years ago
15

The width of a rectangle is 1/2 of its length. What are the sides of the rectangle if its perimeter is 63 in.?

Mathematics
1 answer:
sergejj [24]3 years ago
5 0

Answer:

Width is 10 1/2 inches and the length = 21 inches.

Step-by-step explanation:

Let the width be x then the length us 2x inches.

Perimeter = 2x + 2(2x) = 63

6x = 63

x = 10 1/2 inches.

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Rewrite in simplest radical form square root of x times the fourth root of x. Show each step of your process.
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Answer:

\sqrt[4] {x^3}

Step-by-step explanation:

At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:

\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}

Alternatively, if you're allowed to use rational exponents, we can convert everything:

\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}

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3 years ago
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Step-by-step explanation:

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3 years ago
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Work out the value of 4 lots of 10​
nasty-shy [4]

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40

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How do you find the area of this (it is not 12 or 18) The First answer gets brainliest
bija089 [108]

Answer:

<em><u>ok the area of a trapezoid is 48 </u></em>

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Step-by-step explanation:

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