3 years ago

The width of a rectangle is 1/2 of its length. What are the sides of the rectangle if its perimeter is 63 in.?

1 answer:

5 0

Answer:

Width is 10 1/2 inches and the length = 21 inches.

Step-by-step explanation:

Let the width be x then the length us 2x inches.

Perimeter = 2x + 2(2x) = 63

6x = 63

x = 10 1/2 inches.

You might be interested in

Dimas [21]

The good answer is 9
(9:9=1 and 27:9=3)

3 0

3 years ago

lukranit [14]

2(z - 5) + (z - 8) =

= 2z - 10 + z - 8 =

= 2z + z - 10 - 8 = 3z - 18 ← the end

4 0

3 years ago

sdas [7]

Hope this will help u...:)

5 0

3 years ago

lutik1710 [3]

3r+n2−r+5−2n+2=3r+n2+−r+5+−2n+2=3r+n2+−r+5+−2n+2=(n2)+(−2n)+(3r+−r)+(5+2)=n2+−2n+2r+7
=n2−2n+2r+7

7 0

3 years ago

Strike441 [17]

Answer:

Could you link the table?

Step-by-step explanation:

4 0

3 years ago