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ad-work [718]
3 years ago
12

What is the IMA of the following pulley system?34567

Physics
1 answer:
Lynna [10]3 years ago
6 0

Answer:

    IMA of given system =   \frac{F_{r} }{F_{e} }

Explanation:

  • The "Ideal Mechanical advantage" (IMA) of given pulley is \frac{F_{r} }{F_{e} } .
  • Ideal Mechanical advantage of a system is defined by the ratio of achieved or output force to the implied force. In the pulley system above, output force is the resistant force denoted by F_{r}. The input force is analogous or equivalent to the effort applied i.e. F_{e} .
  • Hence by dividing these two forces we calculate the IMA of the above mentioned pulley system which is  \frac{F_{r} }{F_{e} } .
  • Its mathematical reference would be:

                                                IMA =   \frac{F_{r} }{F_{e} }

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When a 2.50 kg object is hung vertically on a certain light spring described by hookes law the spring stretches 2.76 cm.
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F=K*X,
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24.525=K*0.0276

24.525/0.0276=K

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981N/m 


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If state law mandates that elevators cannot accelerate more than 4.80 m/s2 or travel faster than 19.8 m/s , what is the minimum
Rudik [331]

Answer:

23.0 s

Explanation:

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v₀ = 0 m/s

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v² = v₀² + 2aΔx

(19.8 m/s)² = (0 m/s)² + 2 (4.80 m/s²) Δx

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19.8 m/s = (4.80 m/s²) t + 0 m/s

t = 4.125 s

The elevator takes 40.84 m and 4.125 s to accelerate, and therefore also 40.84 m and 4.125 s to decelerate.

That leaves 291.3 m to travel at top speed.  The time it takes is:

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8 0
3 years ago
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