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Scrat [10]
2 years ago
15

When are children MOST likely to begin using words to express meaning? A. before 12 months B. between 12 and 18 months C. betwee

n 18 months and 2 years D. between 2 and 3 years
Physics
2 answers:
lubasha [3.4K]2 years ago
7 0

Answer:

B. Between 12 and 18 months

Explanation:

I hope this helped!

disa [49]2 years ago
7 0
Answer: B. Between 12 and 18 months
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Which of these is an example of a physical change? Question options: wood decaying iron melting paper burning steel rusting
marin [14]
Im pretty sure burning paper

its either that or melting iron but im 90 percent sure its paper burning
4 0
3 years ago
What is the acceleration of an object in free fall near Earth's surface?
Vitek1552 [10]

Answer:

D 9.8 m/s^2

Explanation:

The force of gravitational gravity on earth is 9.8 m/s^2

8 0
3 years ago
Read 2 more answers
A wind turbine is rotating counterclockwise at 0.626 rev/s and slows to a stop in 12.9 s. Its blades are 17.9 m in length. What
iogann1982 [59]

Answer:

276.5 m/s^2

Explanation:

The initial angular velocity of the turbine is

\omega=0.626 rev/s \cdot 2\pi rad/rev =3.93 rad/s

The length of the blade is

r = 17.9 m

So the centripetal acceleration is given by

a=\omega^2 r

At the instant t = 0,

\omega=3.93 rad/s

So the centripetal acceleration of the tip of the blades is

a=(3.93 rad/s)^2 (17.9 m)=276.5 m/s^2

5 0
2 years ago
A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.
enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, KE_{f} = 0.5mv^{2}

a) Using the principle of energy conservation,

KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

7 0
3 years ago
How does an inclined plane change distance and how does it change direction
ElenaW [278]
 Objects are known to go down because of a unbalanced force
7 0
2 years ago
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