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3 years ago

The photoelectric effect tells us that __________.

Physics

1 answer:

Ivanshal [37]3 years ago

6 0

It describes the process by which surface electron's are emitted from a metal when light is shined on it.
And it tells us that light at a higher intensity must contain more quanta of energy, known as protons.

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gregori [183]

Answer:

1. Revolve around a point

2. Formed from dust and gas particles

3. Exoplanets and associated star orbit a common center of mass

4. Composed of gases found in Jupiter and Saturn

3 0

3 years ago

Convert the following angles in degrees to radians:<br><br>(a) 300°<br>(b) 18°<br>(c) 105°

almond37 [142]

Answer:

a) 5.23599

b) 0.314159

c) 1.8326

Explanation:

5 0

3 years ago

Read 2 more answers

The magnitude of the magnetic flux through the surface of a circular plate is 6.80 10-5 T · m2 when it is placed in a region of

PIT_PIT [208]

Answer:

B = 4.1*10^-3 T = 4.1mT

Explanation:

In order to calculate the strength of the magnetic field, you use the following formula for the magnetic flux trough a surface:

$\Phi_B=S\cdot B=SBcos\alpha$ (1)

ФB: magnetic flux trough the circular surface = 6.80*10^-5 T.m^2

S: surface area of the circular plate = π.r^2

r: radius of the circular plate = 8.50cm = 0.085m

B: magnitude of the magnetic field = ?

α: angle between the direction of the magnetic field and the normal to the surface area of the circular plate = 43.0°

You solve the equation (1) for B, and replace the values of the other parameters:

$B=\frac{\Phi_B}{Scos\alpha}=\frac{6.80*10^{-5}T.m^2}{(\pi (0.085m)^2)cos(43.0\°)}\\\\B=4.1*10^{-3}T=4.1mT$

The strength of the magntetic field is 4.1mT

4 0

3 years ago

PLEASE HELP ASAP!!! NO LINKS! Which type of wave does the illustration depict?

Xelga [282]

Answer:

Transverse wave

Explanation:

The wave is moving forwards from the hand to the point of attachment

3 0

2 years ago

hich of the following statements are true for magnetic force acting on a current-carrying wire in a uniform magnetic field?Check

leonid [27]

Explanation:

The magnetic force acting on a current carrying wire in a uniform magnetic field is given by :

$F=I(L\times B)$

$F=ILB\ sin\theta$

Where

$\theta$ is the angle between length and the magnetic field

The magnetic force is perpendicular to both current and magnetic field. It is maximum when it is perpendicular to both current and magnetic field.

So, the correct options are :

The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
.The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.
The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

7 0

3 years ago