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RoseWind [281]
3 years ago
9

$130.00 coat; 20% discount Find the total cost to the nearest cent.

Mathematics
2 answers:
labwork [276]3 years ago
8 0

Answer:

26

Step-by-step explanation:

130 times 20% is 26

You could also do it like 130 times 0.20 and still get 26

vichka [17]3 years ago
4 0

Answer:

104

Step-by-step explanation:

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-10y<60 (Please solve and show work)
erma4kov [3.2K]
Y can realistically be any positive number, since a negative number multiplied by a positive number's product is negative. a negative number will always be less than a positive number, in this case the positive number being 60.

<span>a negative number multiplied by another negative number's product is positive, so as long as the negative numbers are less than -6 (because -10 times -6 is 60, and 60 is not less than 60) y can be negative.</span>


I hope this helps!
7 0
3 years ago
Read 2 more answers
Create truth table to determine whether or not the following statements are logically equivalent
otez555 [7]

The statement is totally false.

\neg P\lor\neg Q \equiv \neg(P \land Q) \not\equiv P\land Q

because (P and ¬P) is a contradiction.

4 0
2 years ago
51.03 is 88% of what number
Tcecarenko [31]
I would use a proportion

51.03/88% = x/100%

Which is saying: if 51.03 is 88% of the number, what is 100% of the number

Cross multiply to get x=57.99
5 0
3 years ago
Which graph represents the following system of inequalities.
Marta_Voda [28]

Answer: Graph C is correct

Step-by-step explanation:

The region below the dashed red line is y < 4/3x +2

The region below the solid purple line is y ≤ -1

The region below and left of the solid green line is y ≤ -3x

4 0
3 years ago
Help !!!<br>See question in image.<br>Please show workings .<br>​
ivolga24 [154]

Answer:

see explanation

Step-by-step explanation:

Given f(x) then the derivative f'(x) is

f'(x) = lim(h tends to 0 ) \frac{f(x+h)-f(x)}{h}

      = lim ( h to 0 ) \frac{4(x+h)^2-2-(4x^2-2)}{h}

      = lim ( h to 0 ) \frac{4(x+h)^2-2-4x^2+2}{h}

      = lim( h to 0 ) \frac{4x^2+8hx+4h^2-4x^2}{h}

      = lim( h to 0 ) \frac{8hx+4h^2}{h}

      = lim ( h to 0 ) \frac{4h(2x+h)}{h} ← cancel h on numerator/ denominator

      = lim ( h to 0 )  4(2x + h) ← let h go to zero

f'(x) = 8x

5 0
2 years ago
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