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AlladinOne [14]
3 years ago
9

A store offers a 15% discount on their pants. If the pants originally cost $30.00 what will be the discount price of the pants?

(the total cost after the discount)
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

The pants will either be 25.50 or 4.50. Sorry I'm not sure if 15% off 30.00 is the number minus the original price or not.

Step-by-step explanation:

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This would be an algebraic problem if that's what you're asking.

x=8 in this equation.

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7) What is the equation of a circle with the center (-8, 9) and the radius of 10?​
lutik1710 [3]

Answer:

<h3>(x+8)² + (y - 9)² = 100</h3>

Step-by-step explanation:​

The general equation of a circle is expressed as;

(x-a)² + (y - b)² = r² where;

(a, b) is the centre of the circle

r is the radius

Given

Centre (-8, 9) where a = -8, b = 9

radius r = 10

Substitute into the formula to get the required equation;

(x-(-8))² + (y - 9)² = 10²

(x+8))² + (y - 9)² = 10²

(x+8)² + (y - 9)² = 100

Hence the required equation is (x+8)² + (y - 9)² = 100

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Find the Roots of the quadratic equation.<br> 2x2 + 7 – 30 = 0
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Answer:

x=−5/2,6

Step-by-step explanation:

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Charmaine is on the swim team. Each day she swims 950m . How far does she swim in 5 days?
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950m * 5 days = 4750 m = 4.75 km
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A contractor is building a new subdivision on the outside of a city. He has started work on the first street and is planning for
ruslelena [56]

You can use those two given points of street 1 to form its equation, then can use the fact that parallel lines have same slope to find the equation of second street with the help of the point (1,5) which lies in second street.

The equation of the location of the second street in standard form is given as 2y = x + 9

<h3>What is the equation of a straight line passing through two given points?</h3>

Let the two given points be (a,b) and (c,d). Then the equation of straight line passing through these two points is given by:

y - b = \dfrac{(d-b)}{(c-a)}(x-a)

<h3>What is slope intercept form of equation of straight line?</h3>

y = mx + c is the slope intercept form of straight line where m is the slope and c is the y-intercept (where the straight line cut on y = c at y axis) of the given line.

<h3>How to find equation of second street's location in terms of equation of straight line?</h3>

Firstly we will find the equation of straight line which represents street 1.

Since street 1 goes from point (-5,-6) and (3,-2), thus, its equation would be:

y - (-6) = \dfrac{-2- (-6)}{3-(-5)} (x -(-5))\\&#10;\\&#10;y + 6 = \dfrac{1}{2}(x+5)\\&#10;\\&#10;y + 6 = \dfrac{x}{2} + \dfrac{5}{2}\\\\&#10;y = \dfrac{x}{2} -\dfrac{7}{2}

Thus, this above equation represents equation of location of street 1. The slope is 1/2 and y-intercept is -7/2.

Since the street 2 is parallel to street 1, thus we have its slope same as that of street 1. Writing the equation in slope intercept form we get:

y = \dfrac{1}{2}x + c

Since street 2 passes through (1,5)( x=  1, y = 5), thus, this point must satisfy above equation which represents all points lying on street 2.

Thus,

5 = \dfrac{1}{2} \times 1 + c\\\\&#10;c = 5 - \dfrac{1}{2} = \dfrac{9}{2}

Thus, the equation representing points on street 2 is given by:

y = \dfrac{x}{2} + \dfrac{9}{2}\\&#10;\\&#10;2y = x + 9

Learn more about equation of straight line here:

brainly.com/question/19380936

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2 years ago
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