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AlladinOne [14]
3 years ago
9

A store offers a 15% discount on their pants. If the pants originally cost $30.00 what will be the discount price of the pants?

(the total cost after the discount)
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

The pants will either be 25.50 or 4.50. Sorry I'm not sure if 15% off 30.00 is the number minus the original price or not.

Step-by-step explanation:

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Solve <br>|-4b-8|+|-1-b^2|+2b^3. b= -2<br>show steps please .
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Ok, first put in the -2 for each b. That gives:
|-4(-2)-8|+|-1(-(-2))^2|+2(-2)^3
Let's do each section.
The first section is |-4(-2)-8)|
-4 times -2 is 8, minus 8 is 0. The absolute value of 0 is still 0.
Now we move on to |-1(-(-2))^2)|
First we do exponents
-(-2) is 2, and 2^2 is 4. 4 times -1 is -4. The absolute value of -4 is 4
Now the last section, 2(-2)^3
Exponents first: (-2)^3 is -2 * -2 * -2, which is -8.
-8*2=-16.
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Step-by-step explanation:

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Step-by-step explanation:

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What is 845,001 rounded to the nearest hundred thousand
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Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((
Alexus [3.1K]

Answer:

q^{-30}

Step-by-step explanation:

Given the expression:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}

First, we open the outer brackets

=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}

Therefore:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30

8 0
4 years ago
Read 2 more answers
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