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Alenkinab [10]
3 years ago
12

At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 32.8105 cm on a spring with a sprin

g constant of 13.9602 N/m. The mass of the bananas is 49.0943 kg. What is the maximum speed of the bananas?
Physics
1 answer:
Trava [24]3 years ago
3 0

Answer:

0.175 m/s

Explanation:

32.8105 cm = 0.328105 m

According to the law of conservation in energy, as the spring oscillates, its kinetic energy is converted to spring elastic energy and vice versa. So the maximum speed of the bananas occur when spring elastic energy is 0 and vice versa, spring elastic energy is maximum (at amplitude) with kinetic energy, and speed, is 0

E_e = E_k

kx^2/2 = mv^2/2

13.9602*(0.328105)^2/2 = 49.0943v^2/2

v^2 = \frac{13.9602*(0.328105)^2}{49.0943} = 0.0306

v = \sqrt{0.0306} = 0.175 m/s

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What is the approximate value of the gravitational force between a 73 kg astronaut and a 7.1×104 kg spacecraft when they're 89 m
Luden [163]

Answer:

F = 4.3671 * 10^{-8}\ Newtons

Explanation:

The gravitational force between two corpses is given by the following equation:

F = GMm/d^2

Where F is the force, G is the gravitational constant

(G = 6.67408*10^{-11}\ m^3kg^{-1}s^{-2}), M and m are the masses of the corpses and d is the distance between them.

So we have that:

F = 6.67408*10^{-11} * 7.1*10^4 * 73/89^2

F = 4.3671 * 10^{-8}\ Newtons

5 0
3 years ago
An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o
Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

m is the mass of object

m=\dfrac{W}{g}

m=\dfrac{2.45}{9.8}

m = 0.25 kg

k=\dfrac{4\pi^2m}{T^2}

k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}

k = 24.09 N/m

or

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

6 0
2 years ago
(I) In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. A second pro
Kipish [7]

Answer:

The second projectile was 1.41 times faster than the first.

Explanation:

In the ballistic pendulum experiment, the speed (v) of the projectile is given by:  

v = \frac{m + M}{m} \cdot \sqrt{2gh}

<em>where m: is the mass of the projectile, M: is the mass of the pendulum, g: is the gravitational constant and h: is the maximum height of the pendulum.   </em>

To know how many times faster was the second projectile than the first, we need to take the ratio for the velocities for the projectiles 2 and 1:    

\frac{v_{2}}{v_{1}} = \frac{\frac{m_{2} + M}{m_{2}} \cdot \sqrt{2gh_{2}}}{\frac{m_{1} + M}{m_{1}} \cdot \sqrt{2gh_{1}}}           (1)

<em>where m₁ and m₂ are the masses of the projectiles 1 and 2, respectively, and h₁ and h₂ are the maximum height reached by the pendulum by the projectiles 1 and 2, respectively.  </em>

Since the projectile 1 has the same mass that the projectile 2, we can simplify equation (1):

\frac{v_{2}}{v_{1}} = \frac{\sqrt{h_{2}}}{\sqrt{h_{1}}}  

\frac{v_{2}}{v_{1}} = \frac{\sqrt{5.2 cm}}{\sqrt{2.6 cm}}

\frac{v_{2}}{v_{1}} = 1.41  

Therefore, the second projectile was 1.41 times faster than the first.  

I hope it helps you!

8 0
3 years ago
Suppose a blood vessel's radius is decreased to 87% of its original value by plaque deposits and the body compensates by increas
dexar [7]

Answer:

The pressure difference will increase by the factor of 1.75

Explanation:

For constant flow rate, coefficient of viscosity, length of the vessel and the pressure difference is inversely proportional to the fourth power of the radius of the blood vessel

Apply the principle of Poiseuille’s law.

Q = (P2 - P1)/R

Pls check the attached file for step by step solution of the question. It is submitted in this way as typing the equation may not be explanatory.

3 0
3 years ago
Siven an element's atomic number and mass number, how can you tell the number of protons and neutrons in its nucleus?
sukhopar [10]
It would be the first option.

Explanation-
The number of protons is equal to the atomic number the number of neutrons is the mass minus the atomic number.
3 0
3 years ago
Read 2 more answers
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