The force exerted by one plate for two parallel plates arrangement is F = QE/2.
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Force one plate exerts on the other</h3>
The force exerted by one plate for two parallel plates arrangement is given as follows;
F = QE/2
where;
- Q is the charge on one plates
- E is the electric field due to the charge
- F is force exerted by one plate
Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.
Learn more about force between parallel plates here: brainly.com/question/13590045
Work = force * distance
force = 100 N
Distance = 5m
work =100 N* 5m
=500 J
We use the formula,
.
Here, v is velocity and its value given 26 mi/h ( in m/s,
) and d is distance and its value is given 80 m.
Substituting these values in above formula we get,

Thus, the time delay between green lights on successive blocks to keep the traffic moving continuously is 6.88 s
Answer:
Density of 127 I = 
Also, 
Explanation:
Given, the radius of a nucleus is given as
.
where,
- A is the mass number of the nucleus.
The density of the nucleus is defined as the mass of the nucleus M per unit volume V.

For the nucleus 127 I,
Mass, M = 
Mass number, A = 127.
Therefore, the density of the 127 I nucleus is given by

On comparing with the density of the solid iodine,
