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Hitman42 [59]
3 years ago
10

Hydrochloric acid reacts with calcium to form hydrogen and calcium chloride. If 100 grams of hydrochloric acid reacts with 100 g

rams of calcium, what is the limiting reactant? 2HCl + Ca → CaCl2 + H2
Chemistry
2 answers:
Natali5045456 [20]3 years ago
6 0

Answer:- The limiting reactant is HCl.

Explanation: The balanced equation is:

2HCl+Ca\rightarrow CaCl_2+H_2

It's a stoichiometry problem. Masses of both the reactants are given and the questions asks to find out the limiting reactant.

We convert the given grams of each reactant to moles on dividing by its molar mass. Now, we can calculate the moles of any of the product on multiplying the moles of the reactant by mole ratio.

We do this starting with both the reactants and see which one gives less number of moles of the product. The limiting reactant is the one giving least number of moles of the product.

Molar mass of HCl is 36.46 gram per mol and that of Ca is 40.08 gram per mol.

Let's say we calculate the moles of hydrogen gas produced in the reaction. Mole ratio of H_2 to HCl is 1:2 and the mole ratio of H_2 to Ca is 1:1 .

The calculations are as shown below:

100gHCl(\frac{1molHCl}{36.46gHCl})(\frac{1molH_2}{2molHCl})

= 1.37 mol [tex[H_2[/tex]

100gCa(\frac{1molCa}{40.08gCa})(\frac{1molH_2}{1molCa})

= 2.50 mol H_2

From above calculations, we get the least moles of hydrogen gas from 100 grams of HCl. So, the limiting reactant is HCl.

LenaWriter [7]3 years ago
5 0
Answer is hydrochloric acid

Hope this helps!
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The molecule diethyl ether can be represented as it follows, with two ethyl groups (-CH2CH3) bonded to a oxygen atom:

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3 0
1 year ago
Please help me with this chem question, I’ll mark you brainiest if it’s right. There’s multiple answers for this one.
Kazeer [188]

Answer:

Option A. KCl (aq)

Option D. Mg(OH)₂(s

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

MgCl₂(aq) + KOH(aq) —>

In solution, MgCl₂(aq) and KOH(aq) will dissociate as follow:

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

KOH(aq) —> K⁺(aq) + OH¯(aq)

MgCl₂(aq) + KOH(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2K⁺(aq) + OH¯(aq) —> 2K⁺(aq) + 2Cl¯(aq) + Mg(OH)₂ (s)

MgCl₂(aq) + KOH(aq) —> 2KCl (aq) + Mg(OH)₂(s)

Thus, the products of the above reaction are: KCl(aq) and Mg(OH)₂(s)

Thus, option A and D gives the correct answer to the question.

8 0
2 years ago
You conduct an experiment in which you measure the temperature (T) and volume (V) of a mysterious sphere of gas at several diffe
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Volume of the gas is 525 L.

<u>Explanation:</u>

It is given that the volume of the gas divided by the temperature is 1.75.

V/T = 1.75

As per the Charles law, volume is proportional to the temperature.

V ∝ T

V/T = constant

Now we have to find V, and T is given as 300 K.

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Rearranging the equation to get V as,

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Answer:

Mass of ring = 32 g

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Density of ring = 8 g/mL

Explanation:

From the question given above, the following data were obtained:

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Next, we shall determine the volume of the ring. This can be obtained as follow:

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