Based on the balanced chemical reaction presented above, every mole of magnesium (Mg) yields one mole of diatomic hydrogen (H2). When converted to masses, every 24.3 grams of magnesium yields 2 grams of hydrogen.
From the given, there are 20 grams of magnesium available for the reaction. With this amount, the expected yield of hydrogen is 1.646 grams. To calculate the percent yield, divide the actual yield to the hypothetical yield.
*The case is impossible because the actual yield is greater than the theoretical yield.
If we assume that there had been a typographical error and that the actual yield is 0.7 grams instead of 1.7 grams, the percent yield becomes 42.5%. Thus, the answer is letter E.
Answer:
26.81 moles
Explanation:
From the coefficients of the equation, we know that for every 2 moles of iron(III) oxide produced, 7 moles of oxygen are consumed.
So, the answer is 7.66(7/2), which is 26.81 mol.
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The percentage yield of the reaction : 93.3%
Mass of FeCO₃ 2310.44 g
<h3>Further explanation
</h3>
The reaction equation is the chemical formula of reagents and product substances
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products
Reaction
4 FeCO₃ + O₂ ⇒ 2 Fe₂O₃ + 4CO₂
MW FeCO₃ : 115,854 g/mol
MW Fe₂O₃ : 159,69 g/mol
mol of 1 kg Fe₂O₃ = 1000 g
mol of FeCO₃
mass of FeCO₃
a purity of 62.8%
Answer:
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Explanation:
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