<h2>The equation that agrees with the ideal gas law: None of it </h2>
Explanation:
None , of the given equation goes with the ideal gas law .
Ideal gas law
It is the law that gives the relationship between P,V,T and number of moles .
Ideal gas equation
It is the law that is formed by combining Boyle's law , charle's law ,Avgadro's law that is :
P ∝ 1/v
V∝T
V∝n
combining all, we get
PV=nRT
where R is a gas constant .
This is an ideal gas equation ,
- The first option given : V₁/T₁=V₂/T₂
- The second option : V₁n₁=V₂n₂
- The third equation : P₁n₁=P₂n₂
- The fourth option : P₁/T₁=P₂/T₂
none ,of it specifies because ideal gas equation relation is :
P₁V₁/T₁=P₂V₂/T₂ is an ideal gas equation
Answer: flame in a lamp, tube light, electric bulb
Explanation:
Answer:
5 L.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V1) = 10 L
Initial pressure (P1) = 2.5 atm
Final pressure (P2) = 5 atm
Final volume (V2) =.?
Since the temperature is constant, we shall apply the Boyle's law equation to determine the new volume of the gas. This can be obtained as follow:
P1V1 = P2V2
2.5 × 10 = 5 × V2
25 = 5 × V2
Divide both side by 5
V2 =25/5
V2 = 5 L
Thus, the new volume of the gas is 5 L
If 14 grams of hydrogen reacted with 24.7 grams of oxygen 27.7875 grams of water will be formed.
Explanation:
2H2+O2----------->2H2O.
- From the above equation, we can say that 4g of Hydrogen will react with 32 g of oxygen.
- In this question, Hydrogen is in excess amount.
- 32 g of Oxygen will react with = 4 g of H2.
- Therefore 24.7g of Oxygen will react with =24.7x4/32= 3.0875 g H2.
- The remaining 10.9125g of H2 will be left unreacted.
- Therefore the amount of water formed=(24.7+3.0875)=27.7875 g
add all the number and find the average then subtract the mass defect and then you will get your answer
