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belka [17]
3 years ago
7

A laser beam of unknown wavelength passes through adiffraction grating having 5510 lines/cm after striking itperpendicularly. Ta

king measurements, you find that the first pairof bright spots away from the central maximum occurs at±15.4° with respect to the original beam direction. (a) What is the wavelength of thelight? (b) at what angle will the next pair ofbright spots occur?
Physics
1 answer:
Ivahew [28]3 years ago
7 0

Answer:

Explanation:

distance between two slit  d = \frac{1 \times 10^{-2}}{5510}

d = 18.15 x 10⁻⁷ m

Let wave length of light λ

formula for  position of  first pair of bright spot

Tanθ = λ / d , λ is wave length of light and d is distance between two slit .

Tan 15.4 = \frac{\lambda}{18.15\times10^{-7}}

λ = Tan 15.4 x 18.15 x 10⁻⁷

=5 x 10⁻⁷ m

If θ be the position of next bright spot

Tanθ = 2 λ / d

= \frac{2 \times\ 5\times\ 10^ {-7}}{18.15\times10^{-7}}

=\frac{2\times5}{18.5}

θ = 28.4 degree .

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<h3>Calculating the tension in the chains</h3>

From the principle of moments:

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T1 + T2 = 150 + 650 + 419

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The difference is 920nm.

<h3>What is called Wavelength?</h3>

The wavelength can be defined as the separation between wave crests. Additionally, a wide variety of objects move in waves, including light, the earth or ground, water, strings, air, and sound waves. Furthermore, we use the Greek letter lambda to denote the wave's wavelength. In addition, the wave's wavelength is determined by dividing its velocity by its frequency. Additionally, we employ meters (m), which is the unit used to indicate wavelength in meters.

Positive interference is produced by a bright fringe, and the wavelength is always multiple.

The difference at the center fringe is (460 nm)(0) = 0.

The difference for the first maximum is (460 nm)(1) = 460 nm.

The difference for the second maximum is (460 nm)(2) = 920 nm.

As a result, the difference for maxima n is (460 nm) (n)

Since C is on the second maximum in the image that was submitted, the difference is stated as (460 nm)(2) = 920 nm.

Consequently, the screen's central dot on the fringe E to the left slit is 920 nm.

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