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3 years ago

If a force of 450N pushes a box 4 meters in 2 seconds, how much power was developed?

1 answer:

5 0

Work = (force) x (distance) = (450 N) x (4 m) = 1,800 joules

Power = (work) / (time) = (1,800 joules) / (2 sec) = 900 watts .

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The period of a simple pendulum, defined as the time necessary for one complete oscillation, is measured in time units and is gi

Oksana_A [137]

The task is to show that the right side of the equation has units of [Time], just like the left side has.

The right side of the equation is . . . 2 π √(L/G) .

We can completely ignore the 2π since it has no units at all, so it has no effect on the units of the right side of the equation. Now the task is simply to find the units of √(L/G) .

L . . . meters

G . . . meters/sec²

(L/G) = (meters) / (meters/sec²)

(L/G) = (meters) · (sec²/meters)

(L/G) = (meters · sec²) / (meters)

(L/G) = sec²

So √(L/G) = seconds = [Time]

THAT's what we were hoping to prove, and we did it !

7 0

3 years ago

1) A net force of 75.5 N is applied horizontally to slide a 225 kg crate across the floor.

dimulka [17.4K]

Answer:

The acceleration of the crate is $0.3356\,\frac{m}{s^2}$

Explanation:

Recall the formula that relates force,mass and acceleration from newton's second law;

$F=m\,a$

Then in our case, we know the force applied and we know the mass of the crate, so we can solve for the acceleration as shown below:

$F=m\,a\\75.5\,N=225\,\,kg\,\,a\\a=\frac{75.5}{225} \,\frac{m}{s^2} \\a=0.3356\,\,\frac{m}{s^2}$

7 0

3 years ago

I need help!!!! I don’t understand physical science at all.

allochka39001 [22]

B is the correct answer

3 0

3 years ago

A horizontal force of 50 N is applied to the object.

USPshnik [31]

Answer:

Mass of object (m) = 5.102 kg

Explanation:

Given:

Horizontal Force (F) = 50 N

Find:

Mass of object (m) = ?

Computation:

We know that, acceleration due to gravity (g) = 9.8 m/s²

⇒ Horizontal Force (F) = mg

⇒ 50 N = m (9.8 m/s²)

⇒ Mass of object (m) = 50 / 9.8

⇒ Mass of object (m) = 5.102 kg

Mass of object (m) is 5.1 kg (Approx)

3 0

4 years ago

Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where l

goblinko [34]

Answer:

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Explanation:

The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.

$\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}$

where,

Δt = required time interval = ?

Δs = distance between ears = 18 cm = 0.18 m

v = speed of sound = 340 m/s

Therefore,

$\Delta t = \frac{0.18\ m}{340\ m/s}$

4 0

3 years ago