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tiny-mole [99]
3 years ago
12

If a force of 450N pushes a box 4 meters in 2 seconds, how much power was developed?

Physics
1 answer:
strojnjashka [21]3 years ago
5 0

Work = (force) x (distance) = (450 N) x (4 m) = 1,800 joules

Power = (work) / (time) = (1,800 joules) / (2 sec) = 900 watts .
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During an experiment, an object is placed on a disk that rotates about an axle through its center, as shown in Figure 1. The dis
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B. 0.72 N

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An aluminum rod of length 3.3 m and crosssectional area 3.8 cm2 is inserted vertically into a thermally insulated vessel contain
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Answer:

V_vap = 161.2 L

Explanation:

The total mass of the aluminum rod is given as;

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Where;

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By cooling down the submerged half of the aluminum rod releases an heat amount of

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Where;

cp is specific heat of aluminum aluminum = 900 J/kg

∆T is change in temperature = 274 - 4.2 = 269.8 K

Thus;

Q = (1/2)•3.3858•900•(269.8)

= 411069.978 J

The liquid absorbs this heat and vaporizes partially, such that the heat equals vaporized mass times latent heat of vaporization:

Q = m_vap•∆h_vap

Making m_vap the subject;

m_vap∙ = Q/∆h_vap

Where ∆h_vap is latent heat of vaporization given as 20900J/kg

Thus,

m_vap∙ = 411069.978/20900

= 19.668 kg

Let's divide this mass by the density of liquid helium and we get the liquid volume which has vaporized:

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V_vap∙ = 19.668/122

V_vap∙ = 0.1612 m³

Converting to litres;

V_vap = 0.1612 x 1000

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Options A and B.

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Explanation:

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