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3 years ago

Please answer giving all my points for it

Physics

2 answers:

Galina-37 [17]3 years ago

7 0

1. It would be 6

2. f - p (D)

The one on the bottom that you answered is right.

Papessa [141]3 years ago

6 0

A. 2

B. F - f

Hope this helps!

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A 20 kg crate initially at rest on a horizontal floor requires a 80 N horizontal force to set it in motion. Find the coefficient

e-lub [12.9K]

Answer:

The coefficient of static friction between the crate and the floor is 0.41

Explanation:

Friction Force

When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration and velocity because the friction force opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

$Fr=\mu N$ [1]

Where $\mu$ is the coefficient of static or kinetics friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W = m.g

The crate of m=20 Kg has a weight of:

W = 20*9.8

W = 196 N

The normal force is also N=196 N

We can find the coefficient of static friction by solving [1] for $\mu$ :

$\displaystyle \mu=\frac{Fr}{N}$

The friction force is equal to the minimum force required to start moving the object on the floor, thus Fr=80 N and:

$\displaystyle \mu=\frac{80}{196}$

$\mu=0.41$

The coefficient of static friction between the crate and the floor is 0.41

7 0

3 years ago

Batman chased the joker on his batbike for 20 minutes, traveling at the speed of 30 kilometers per minute. How far did Batman go

AURORKA [14]

Answer:

123 kilometer

Explanation:

none

8 0

3 years ago

Give two examples where friction is a nuisance

dlinn [17]

Answer:

it can cause wear and tear and reduces efficiency as energy is lost.

Explanation:

8 0

3 years ago

A child and sled with a combined mass of 50.0 kg slide down a frictionless slope. if the sled starts from rest and has a speed o

Furkat [3]

Using conservation of energy

Potential Energy (Before) = Kinetic Energy (After)

mgh = 0.5mv^2

divide both sides by m

gh = 0.5v^2

h = (0.5V^2)/g

h = (0.5*2.2^2)/9.81

h = 0.25m

4 0

3 years ago

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Once potential energy is lost on a roller coaster it cannot be gained all the way back true or false

nignag [31]

Answer:

true

Explanation:

because the roller coaster can't work without energy

4 0

3 years ago