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astraxan [27]
3 years ago
7

A person trapped outside during a thunderstorm should

Physics
2 answers:
Katyanochek1 [597]3 years ago
6 0

Answer:

should stay away from trees, water, and tall objects.

irakobra [83]3 years ago
3 0

Answer: the answer is

<h2><u>stay away from trees, water, and tall objects.</u></h2><h2>:)</h2>

Explanation:

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a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported​
oksano4ka [1.4K]

Answer:

Explanation:

You can calculate the total electric charge that passes through the conductor as q=It=(180\times 10^{-3})(5\times 60)= 54 C. It means that the number of electron that passes through the conductor is:

n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}

8 0
2 years ago
Two people must have the same speed and velocity if
RideAnS [48]
If they both are moving with the same speed and direction
i.e. covering the same distance in the same time interval in the same direction
7 0
3 years ago
Read 2 more answers
Calculate the acceleration of a 270000-kg jumbo jet just before takeoff when the thrust on the aircraft is 160000 N .
Radda [10]

Answer:

<h3>The answer is 0.59 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{160000}{270000}  =  \frac{16}{27}  \\  = 0.592592...

We have the final answer as

<h3>0.59 m/s²</h3>

Hope this helps you

7 0
3 years ago
An acorn with a mass of .0300 kg is hanging from a branch in a tree it is 2.50 M off the ground what is the potential energy of
Alekssandra [29.7K]
According to another source this is what I got
<span>0.735 J ( Ep-potential energy, m-mass,g-gravitational acceleration = 9.81m/s², h-height; Ep = m * g * h; Ep = 0.0300 kg * 9.81 m/s² * 2.5 m ) 
</span>Hope it helps
5 0
3 years ago
Read 2 more answers
A horizontal aquifer is overlain by 73.5 ft of water-saturated clay with a porosity of 0.4. The solid density of the clay partic
mr_godi [17]

Answer:

Explanation:

solution is in the attachment below

5 0
3 years ago
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