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yanalaym [24]
3 years ago
13

Which statement best describes electrons?(1) They are positive subatomic particles and are found in the nucleus.(2) They are pos

itive subatomic particles and are found surroundingthe nucleus.(3) They are negative subatomic particles and are found in thenucleus.(4) They are negative subatomic particles and are found surrounding the nucleus.
Chemistry
1 answer:
Anton [14]3 years ago
6 0
The answer should be (4) they are negative subatomic particles and are found surrounding the nucleus. The nucleus is formed by neutrons and protons. Neutrons are neutral and protons are positive.
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If pressure is kept constant and the temperature of a gas is doubled, what will happen
weqwewe [10]

I believe it's (A). It will double.

Explanation:

Charles law states that the volume of an ideal gas is directly proportional to the absolute temperature at constant pressure. (Charles's law).

5 0
3 years ago
0.750mol of gas are stored in a tank at a pressure of 275kpa and a temperature of 0.00 degrees * C What is the volume of the tan
nordsb [41]

Answer:

The volume on the tank is 6, 20 L

Explanation:

We use the formula PV=nRT. We convert the units of pressure in kPa into atm and temperature in Celsius into Kelvin:

0°C=273K

101,325kPa---1 atm

275kPa --------x=(275kPax 1 atm)/101,325kPa= 2,71 atm

PV=nRT --> V=nRT/P

V= 0,750 mol x 0,082 l atm /K mol x 273 K/ 2, 71 atm= <em>6, 20 L</em>

4 0
3 years ago
2. This graph shows the energy involved in a reaction involving two molecules. Describe what is happening or what the state of t
blagie [28]
If you think of it endothermic is when there is energy needed for the reaction to occur and exothermic is when the reaction releases energy
6 0
3 years ago
Calculate E ° for the half‑reaction, AgCl ( s ) + e − − ⇀ ↽ − Ag ( s ) + Cl − ( aq ) given that the solubility product constant
antoniya [11.8K]

Answer: The value of E^{o} for the half-cell reaction is 0.222 V.

Explanation:

Equation for solubility equilibrium is as follows.

          AgCl(s) \rightleftharpoons Ag^{+}(aq) + Cl^{-}(aq)

Its solubility product will be as follows.

       K_{sp} = [Ag^{+}][Cl^{-}]

Cell reaction for this equation is as follows.

     Ag(s)| AgCl(s)|Cl^{-}(0.1 M)|| Ag^{+}(1.0 M)| Ag(s)

Reduction half-reaction: Ag^{+} + 1e^{-} \rightarrow Ag(s),  E^{o}_{Ag^{+}/Ag} = 0.799 V

Oxidation half-reaction: Ag(s) + Cl^{-}(aq) \rightarrow AgCl(s) + 1e^{-},   E^{o}_{AgCl/Ag} = ?

Cell reaction: Ag^{+}(aq) + Cl^{-}(aq) \rightarrow AgCl(s)

So, for this cell reaction the number of moles of electrons transferred are n = 1.

    Solubility product, K_{sp} = [Ag^{+}][Cl^{-}]

                                               = 1.77 \times 10^{-10}

Therefore, according to the Nernst equation

           E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}

At equilibrium, E_{cell} = 0.00 V

Putting the given values into the above formula as follows.

         E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}

        0.00 = E^{o}_{cell} - \frac{0.0592 V}{1} log \frac{1}{[Ag^{+}][Cl^{-}]}    

       E^{o}_{cell} = \frac{0.0592}{1} log \frac{1}{K_{sp}}

                  = 0.0591 V \times log \frac{1}{1.77 \times 10^{-10}}

                  = 0.577 V

Hence, we will calculate the standard cell potential as follows.

           E^{o}_{cell} = E^{o}_{cathode} - E^{o}_{anode}

       0.577 V = E^{o}_{Ag^{+}/Ag} - E^{o}_{AgCl/Ag}

       0.577 V = 0.799 V - E^{o}_{AgCl/Ag}

       E^{o}_{AgCl/Ag} = 0.222 V

Thus, we can conclude that value of E^{o} for the half-cell reaction is 0.222 V.

3 0
3 years ago
No copy on goógle:)..
svetlana [45]

Bach's music displays great emotions

Answer:

Explanation:

6 0
3 years ago
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