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3 years ago

Which subatomic particle identifies the atom

Chemistry

1 answer:

Sergio [31]3 years ago

3 0

Answer:

proton

Explanation:

The atoms is made from a nucleus and a electronic shell. The nucleus is composed from protons (positively charged) and neutrons (no charge). The electronic shell is defined by the presence of electrons (negativity charged).

Now a particular element is identified by the number of protons which have to be equal to the number of electrons in the electronic shell. A particular element may have the same number of protons but different number of neutrons, these are isotopes which have the same chemical properties.

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Which of the following organisms would NOT be in the first trophic level of an energy pyramid?

faust18 [17]

dog!

this is because the first energy comes from plants bc they can make their own food— therefore, energy :)

7 0

3 years ago

Read 2 more answers

Negatively charged Adam or group of Adams is called a(n)

bija089 [108]

Answer:

Anion

Explanation:

Anion is an atom or group of atoms that are negatively charged.

Cations are positively charged

Anode is a positively charged pole that conducts electricity (remember electrolysis)

Cathode is a negatively charged pole that conducts electricity (remember electrolysis too)

3 0

3 years ago

Show, in a step by step fashion, your calculations to determine the percent

marusya05 [52]

The percent by volume of a solution : 19.23%

<h3>Further explanation</h3>

Given

50 ml of ethanol

210 ml of water

Required

The percent by volume of a solution

Solution

Percent Volume (% v/v) : volume (ml) of solute/100 ml of solution ⇒ ratio of the volume of the solute to total volume of the solution

$\tt \%solute(v/v)=\dfrac{solute~volume}{solution~volume}\times 100\%$

solute= Ethanol

solvent=water

Solution = solute+solvent

Total volume of the solution :

$\tt =volume~of~Ethanol+solume~of~water\\\\=50~ml+210~ml\\\\=260~ml$

Percent by volume :

$\tt \%volume=\dfrac{50}{260}\times 100\%\\\\\%volume=19.23\%$

8 0

3 years ago

Assume that each atom is a sphere, and that the surface of each atom is in contact with its nearest neighbor. Determine the perc

tatiyna

Answer:

The percentage of unit cell volume that is occupied by atoms in a face- centered cubic lattice is 74.05%
The percentage of unit cell volume that is occupied by atoms in a body-centered cubic lattice is 68.03%
The percentage of unit cell volume that is occupied by atoms in a diamond lattice is 34.01%

Explanation:

The percentage of unit cell volume = Volume of atoms/Volume of unit cell

Volume of sphere = $\frac{4 }{3} \pi r^2$

a) Percentage of unit cell volume occupied by atoms in face- centered cubic lattice:

let the side of each cube = a

Volume of unit cell = Volume of cube = a³

Radius of atoms = $\frac{a\sqrt{2} }{4}$

Volume of each atom = $\frac{4 }{3} \pi (\frac{a\sqrt{2}}{4})^3$ = $\frac{\pi *a^3\sqrt{2}}{24}$

Number of atoms/unit cell = 4

Total volume of the atoms = $4 X \frac{\pi *a^3\sqrt{2}}{24} = \frac{\pi *a^3\sqrt{2}}{6}$

The percentage of unit cell volume = $\frac{\frac{\pi *a^3\sqrt{2}}{6}}{a^3} =\frac{\pi *a^3\sqrt{2}}{6a^3} = \frac{\pi \sqrt{2}}{6}$ = 0.7405

= 0.7405 X 100% = 74.05%

b) Percentage of unit cell volume occupied by atoms in a body-centered cubic lattice

Radius of atoms = $\frac{a\sqrt{3} }{4}$

Volume of each atom = $\frac{4 }{3} \pi (\frac{a\sqrt{3}}{4})^3$ = $\frac{\pi *a^3\sqrt{3}}{16}$

Number of atoms/unit cell = 2

Total volume of the atoms = $2X \frac{\pi *a^3\sqrt{3}}{16} = \frac{\pi *a^3\sqrt{3}}{8}$

The percentage of unit cell volume = $\frac{\frac{\pi *a^3\sqrt{3}}{8}}{a^3} =\frac{\pi *a^3\sqrt{3}}{8a^3} = \frac{\pi \sqrt{3}}{8}$ = 0.6803

= 0.6803 X 100% = 68.03%

c) Percentage of unit cell volume occupied by atoms in a diamond lattice

Radius of atoms = $\frac{a\sqrt{3} }{8}$

Volume of each atom = $\frac{4 }{3} \pi (\frac{a\sqrt{3}}{8})^3$ = $\frac{\pi *a^3\sqrt{3}}{128}$

Number of atoms/unit cell = 8

Total volume of the atoms = $8X \frac{\pi *a^3\sqrt{3}}{128} = \frac{\pi *a^3\sqrt{3}}{16}$

The percentage of unit cell volume = $\frac{\frac{\pi *a^3\sqrt{3}}{16}}{a^3} =\frac{\pi *a^3\sqrt{3}}{16a^3} = \frac{\pi \sqrt{3}}{16}$ = 0.3401

= 0.3401 X 100% = 34.01%

4 0

3 years ago

Can you help me come up with at least three questions about potential and kinetic energy?

Phoenix [80]

Questions:

1) Kinetic energy is the energy an object has due to its ________.

2) Kinetic energy can be calculated from what two measurements?

3) What is the standard unit of measurement for kinetic energy?

4) What would happen to the kinetic energy of an object if you doubled the mass?

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Answers:

1) Motion

2) Velocity and mass

3) Joule

4) The kinetic energy would double

4 0

3 years ago