Answer:
I think -7 N. Netforce is 3N-10N= -7N
Explanation:
<span>Using conservation of energy and momentum you can solve this question. M_l = mass of linebacker
M_ h = mass of halfback
V_l = velocity of linebacker
V_h = velocity of halfback
So for conservation of momentum,
rho = mv
M_l x V_li + M_h x V_hi = M_l x V_lf + M_h x V_hf
For conservation of energy (kinetic)
E_k = 1/2mv^2/ 1/2mV_li^2 + 1/2mV_{hi}^2 = 1/2mV_{lf}^2 + 1/2mV_{hf}^2
Where i and h stand for initial and final values.
We are already told the masses, \[M_l = 110kg\] \[M_h = 85kg\] and the final velocities \[V_{fi} = 8.5ms^{-1}\] and \[V_{ih} = 7.2ms^{-1} </span>
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Since the process occurs at constant pressure, the work done by the gas on the piston is given by

where
W is the work
p is the pressure

is the final volume

is the initial volume
In our problem, we have



(where the negative sign means the work is done by the piston on the gas)
We can re-arrange the previous equation and use these values to find the pressure:
Answer:
The ball is moving in a horizontal circle.
The force acting towards the center of the circle is
F = M a = M * V^2 / R
a = V^2 / R simplifying equation
V = (a / R)^1/2 = (23 / .66)^1/2 = 5.90 m/s