It has holes (an electron deficiency).
Answer:
The moment of inertia about the rotation axis is 117.45 kg-m²
Explanation:
Given that,
Mass of one child = 16 kg
Mass of second child = 24 kg
Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.
We need to calculate the moment of inertia
Using formula of moment of inertia


m = mass of seat
m₁ =mass of one child
m₂ = mass of second child
r = radius of rod
Put the value into the formula


Hence, The moment of inertia about the rotation axis is 117.45 kg-m²
Answer:

ω = 0.0347 rad/s²
a ≅ 1.07 m/s²
Explanation:
Given that:
mass of the model airplane = 0.741 kg
radius of the wire = 30.9 m
Force = 0.795 N
The torque produced by the net thrust about the center of the circle can be calculated as:

where;
F represent the magnitude of the thrust
r represent the radius of the wire
Since we have our parameters in set, the next thing to do is to replace it into the above formula;
So;


(b)
Find the angular acceleration of the airplane when it is in level flight rad/s²

where;
I = moment of inertia
ω = angular acceleration
The moment of inertia (I) can also be illustrated as:

I = ( 0.741) × (30.9)²
I = 0.741 × 954.81
I = 707.51 Kg.m²

Making angular acceleration the subject of the formula; we have;

ω = 
ω = 0.0347 rad/s²
(c)
Find the linear acceleration of the airplane tangent to its flight path.m/s²
the linear acceleration (a) can be given as:
a = ωr
a = 0.0347 × 30.9
a = 1.07223 m/s²
a ≅ 1.07 m/s²
Answer: 160 m
Explanation: First find time or t using the formula for acceleration:
a = vf - vi / t
So t is equal to:
t = vf - vi / a
= 0 m/s - 20 m/s / -2.5 m/s²
= 8 s
To find the distance use the formula for velocity:
v = d / t
Derive for d:
d = v x t
= 20 m/s x 8 s
= 160 m
Answer:
The 500 would be able to keep a light bulb on longer.
Explanation:
The 500 would be able to hold more charge than the 100 which means it can keep the light bulb lit for longer.