A weightlifter takes 0.5s to raise a barbell with 2 free-weights from the ground to a height of 0.9m. If each free-weight has a
1 answer:
Answer:
P = 1412.82 [Watt]
Explanation:
First we must calculate the total mass that makes up the barbell and the two free weights at each end of the barbell.
Weight is now defined as the product of mass by gravitational acceleration.
where:
m = mass = 80 [kg]
g = gravity acceleration = 9.81 [m/s²]
Now using the product of the weight by the distance traveled we can calculate the work.
where:
W = work [J]
w = weight = 784.8 [N]
d = distance = 0.9 [m]
And power is defined as the relationship of work at a certain time. The potency is expressed by means of the following formula.
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Substitute 1.50×10⁹ for n and 1.6×10⁻¹⁹C for e.
The potential difference V between the disks separated by a distance d is given by,
here, E is the electric field.
Substitute 2.00×10⁵N/C for E and 0.50×10⁻³m for d.
The capacitance C of the capacitor is given by,
The capacitance of a parallel plate capacitor is given by,
Here, ε₀ is the permittivity of free space and A is the area of the disks.
Rewrite the expression for A.
the area A of the disks is given by,
Here, D is the diameter of the disk.
The diameter of each disc is found to be 1.32 cm.