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andrew-mc [135]
3 years ago
6

A weightlifter takes 0.5s to raise a barbell with 2 free-weights from the ground to a height of 0.9m. If each free-weight has a

mass of 30kg and the barbell has a mass of 20kg, calculate how much power the weightlifter produces when lifting the barbell?​
Physics
1 answer:
Anna [14]3 years ago
5 0

Answer:

P = 1412.82 [Watt]

Explanation:

First we must calculate the total mass that makes up the barbell and the two free weights at each end of the barbell.

m=30+30+20\\m= 80 [kg]

Weight is now defined as the product of mass by gravitational acceleration.

w=m*g

where:

m = mass = 80 [kg]

g = gravity acceleration = 9.81 [m/s²]

w=80*9.81\\w=784.8[N]

Now using the product of the weight by the distance traveled we can calculate the work.

W=w*d

where:

W = work [J]

w = weight = 784.8 [N]

d = distance = 0.9 [m]

W=784.8*0.9\\W=706.41[J]

And power is defined as the relationship of work at a certain time. The potency is expressed by means of the following formula.

P=W/t\\P=706.41/0.5\\P=1412.82[W]

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Answer:

Your friend is 2.143 blocks from the restaurant.

You are 2.857 blocks from the restaurant.

Explanation:

Let t be the time both you and your friend take to walk to the restaurant.

The distance (m) from your building to the restaurant is your walking time t times your speed v1

s_1 = v_1t = 1.6t

Similarly the distance (m) from your friend building to the restaurant:

s_2 = v_2t = 1.2t

Let b be the length (in m) of a block, the total distance of 5 blocks is 5b

s_1 + s_2 = 5b

1.6t + 1.2t = 5b

2.8t = 5b

t = 5b/2.8 = 25b/14

s_2 = 1.2t = 1.2(25b/14) = 2.143b

So your friend are 2.143b meters from the restaurant, since each block is b meters long, 2.143b meters would equals to 2.143b/b = 2.143 blocks. And you are 5 - 2.143 = 2.857 blocks from the restaurant.

7 0
3 years ago
Seema knows the mass of a basketball. What other information is needed to find the ball’s potential energy? the volume and heigh
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A ball is thrown straight up with enough speed so that it is in the air for several seconds. Assume the positive direction is up
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Answer:

a) v= 0 m/s b) v= 6.86 m/s

Explanation:

a) When the ball reaches to its highest point, under the influence of gravity, before starting to fall down, it momentarily comes to an stop (this is needed prior to change direction in any movement), so, applying the definition of acceleration, and replacing the acceleration a by g, we have:

vf = v₀ - g*t (1)

The minus sign means that the acceleration due to gravity is always downward, so if we assume that the positive direction is upwards it must be negative.

At the highest point, vf= 0.

b) Prior to solve this point, we need to know which is the time when the ball reaches to its highest point.

As we know vf=0, we can solve (1) for t, as follows:

th = v₀/g

Now, for a time that is 0.7 s before this time, applying the acceleration definition and solving for v again, we have:

v = v₀ -(g *(th-0.7 s)), but th= v₀/g, so we get:

v= v₀ -g((v₀/g)-0.7 s) = v₀ - v₀ + g*0.7 s

⇒ v=g*0.7 s = 9.8 m/s²*0.7 s

⇒ v = 6.86 m/s

6 0
3 years ago
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