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matrenka [14]
3 years ago
13

Please help me...

Physics
1 answer:
Naddik [55]3 years ago
4 0

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Please help!
nignag [31]
Since there is no air resistance, gravity is the only force acting on the two objects - the bowling ball and the arrow. Therefore, they will hit the ground at the same time. Thus the answer is D. Both hit the ground at the same time. Hope this helped and have a great day!
5 0
3 years ago
Read 2 more answers
A solar flare is a sudden, rapid, and intense change in the brightness of the sun. Which of these is most
nikdorinn [45]

Answer:

electronic communications may be disrupted

Explanation:

Solar Flares: They occur when the magnetic field lines carrying charged particle entangle and reorganize over the photosphere of the Sun. In these flares charged particles leave the surface of the Sun to travel outwards.

If these flares are directed towards Earth, they will interact with anything related to electricity and magnetism. Out of the given options third option is correct as the electronic communication will be disrupted. If the flares are strong a complete power blackout may occur and that would disrupt all the communication channel and power transmission. Such events have occurred in the past as well.

8 0
3 years ago
Why is the moon's umbra much smaller during a solar eclipse?
Stolb23 [73]

Answer:

the sun is larger than the moon so it creates a shadow

7 0
2 years ago
An air conditioner operating at steady state maintains a dwelling at 70oF on a day when the outside temperature is 90oF. If the
torisob [31]
30000 btuh /3413 btuh/kw. = 8.8 kw

8.8 kw/.746 kw/hp = 11.8 hp if COP is 1

11.8/3 hp (COP coefficient of performance) = 3.99 COP

>>>So yes a 3.0 hp compressor with a nominal COP of 4 will handle the 30,000 btuh load.

3.2 to 4.5 is expected COP range for an air cooled heat pump or a/c unit.
8 0
3 years ago
A 5.45-g combustible sample is burned in a calorimeter. the heat generated changes the temperature of 555 g of water from 20.5°c
Y_Kistochka [10]
Given:
m = 555 g, the mass of water in the calorimeter
ΔT = 39.5 - 20.5 = 19 °C, temperature change
c = 4.18 J/(°C-g), specific heat of  water

Assume that all generated heat goes into heating the water.
Then the energy released is
Q = mcΔT
    = (555 g)*(4.18 J/(°C-g)*(19 °C)
    = 44,078.1 J
    = 44,100 J (approximately)

Answer:  44,100 J

3 0
3 years ago
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