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matrenka [14]
2 years ago
13

Please help me...

Physics
1 answer:
Naddik [55]2 years ago
4 0

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If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol
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Answer:

The maximum wavelength is 492 nm.

Explanation:

Given that,

Angular separation \theta=3.0\times10^{-5}\ rad

Suppose a telescope with a small circular aperture of diameter 2.0 cm.

We need to calculate the maximum wavelength

Using formula of angular separation

\sin\theta=\dfrac{1.22\lambda}{d}

\lambda=\dfrac{d\sin\theta}{1.22}

Put the value into the formula

\lambda=\dfrac{2.0\times\sin(3\times10^{-5})}{1.22}

For small angle \sin\theta\approx\theta

\lambda=\dfrac{0.02\times3\times10^{-5}}{1.22}

\lambda=4.92\times10^{-7}\ m

\lambda=492\ nm

Hence, The maximum wavelength is 492 nm.

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3 years ago
A reconnaissance plane flies 545 km away from
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Answer:

681.6/ms

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Answer in its of m/s

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