The formula used for finding the tangential speed (speed of something that is moving in a circular path) of an orbiting object is:
V₍t₎ = ωr
V₍t₎ = tangential speed or velocity
ω = angular velocity
r = radius of the circular path
if time taken t is only given then use this formula to calculate the tangential speed:
V₍t₎ = 2πr/t, t is time taken
Answer:
The problem with her grandfather's eye can be long sightedness and short sightedness
Explanation:
Given that,
Mona's grandfather had been complaining of poor vision for many days.
We know that,
Refractive eye surgery is small surgery.
We need to find the problem with her grandfather's eye
Using given data,
Mona's grandfather had been complaining of poor vision for many days.
So, the doctor did refractive eye surgery of her grandfather's eye.
Due to this surgery, Mona's grandfather can see things clearly.
Refractive eye surgery is a method for correcting vision.
This surgery used for better vision.
This surgery is possible for long sightedness and short sightedness.
Hence, The problem with her grandfather's eye can be long sightedness and short sightedness
Answer:
6.18 m/s
Explanation:
Given that a ferry approaches shore, moving north with a speed of 6.1 m/s relative to the dock. A person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.0 m/s relative to the ferry Part. What is the speed of the person relative to the dock?
The speed of the person can be calculated by using pythagorean theorem.
Let the speed of the person = S
S^2 = 6.1^2 + 1^2
S^2 = 38.21
S = sqrt ( 38.21)
S = 6.18 m/s
Therefore, the speed of the person relative to the dock is 6.18 m/s
