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GuDViN [60]
2 years ago
15

A 10-N force is needed to move an object with a constant velocity of 5.0 m/s. What power must be delivered to the object by the

force
Physics
1 answer:
vagabundo [1.1K]2 years ago
5 0

The power that must be delivered to the object by the force is 50 W

Power is defined as the rate of doing work. The power of an object in relation to the force and velocity is given by the following equation:

Power (P) = Force (F) × velocity (v)

P = F × v

From the question given above, the following data were obtained:

  • Force (F) = 10 N
  • Velocity (v) = 5 m/s
  • Power (P) =?

P = F × v

P = 10 × 5

<h3>P = 50 W </h3>

Thus, the power that must be delivered to the object by the force is 50 W

Learn more on power: brainly.com/question/19539420

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What average force did the block exert on the bullet if it took a time ∆t to stop the bullet?
PtichkaEL [24]

The average force is \frac{-mv_0}{\Delta t}

Explanation:

We can solve this problem by applying the impulse theorem, which states that the impulse exerted on the bullet (product of force and time) is equal to the change in momentum of the bullet:

F\Delta t = m(v-u)

where

F is the average force exerted by the block on the bullet

\Delta t is the duration of the collision

m is the mass of the bullet

v is its final velocity

u is its initial velocity

Here we have:

m = m

u=v_0

v = 0 (the bullet comes to rest)

And solving for F, we find the average  force:

F=\frac{m(v-u)}{\Delta t}=\frac{-mv_0}{\Delta t}

where the negative sign means the direction of the force is opposite to the direction of motion of the bullet.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

5 0
3 years ago
A girl of mass 60 kg throws a ball of mass 0.8 kg against a wall. The ball strikes the wall horizontally with a speed of 11 m/s,
True [87]

Answer:

352 N

Explanation:

From Newton's second law of motion,

F = m(v-u)/t................ Equation 1

Where F = Average force exerted on the wall by the ball, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time of contact of the ball with the wall.

From the question,

Assuming: The direction of the initial velocity to be negative

Given: m = 0.8 kg, u = -11 m/s, v = 11 m/s (bounce back with the same speed), t = 0.05 s

Substitute into equation 1

F = 0.8[11-(-11)]/0.05

F = 0.8(11+11)/0.05

F = 0.8(22)/0.05

F = 352 N

Hence the average force = 352 N

5 0
4 years ago
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