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xenn [34]
3 years ago
5

SOLVE THE PROBLEM

Physics
1 answer:
Effectus [21]3 years ago
5 0

Answer:

The wavelength in the water compared to when its in the air is: 1160 m/s more

~I hope this is correct and has helped you, have a good day/night~

Explanation:

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The solar noon solar radiation values at the top of the atmosphere above maun are 1366 wm−2 on february 2 and 1074 wm−2 on augus
PilotLPTM [1.2K]

You haven't stated any numbers showing that the intensity of solar radiation at the surface is lower than at the top of the atmosphere. Your data only show that the value at the top of the atmosphere is different on different dates.

From our vast experience, however, we do know that the solar intensity at the surface IS lower than it is at the top of the atmosphere, simply because the atmosphere absorbs some solar radiation ... different amounts of it at different wavelengths.

That's the main reason, for example, why the sky is red at sunrise and sunset and blue the rest of the day, and why the temperature of the air is so much higher than 3° absolute, and why we aren't broiled by X-rays all day. Also the reason why it's worth the tremendous cost and makes such a difference to build astronomical observatories on mountain tops and in low-Earth-orbit, instead of in convenient deep valleys.

8 0
3 years ago
Light from a laser strikes a diffraction grating that has 5500 lines per centimeter. The central and first-order maxima are sepa
WINSTONCH [101]

.Answer:

491.4 nm

Explanation:

The distance between central and first maxima is,

y=0.455m

And the distance between screen abnd grating is,

L=1.62 m

Now the angle can be find as,

tan\theta=\frac{y}{L} \\\theta=tan^{-1}(\frac{0.455}{1.62})  \\\theta=15.68^{\circ}

Now the grating distance is,

d=\frac{1}{5500} cm\\d=1.82\times 10^{-6}m

Now with m=1 condition will become,

\lambda=dsin\theta

So,

\lambda=1.82\times 10^{-6}m\times sin(15.68^{\circ})\\\lambda=1.82\times 10^{-6}m\times 0.270\\\lambda=491.4\times 10^{-9}m\\\lambda=491.4 nm

Therefore the wavelength of laser light is 491.4 nm.

3 0
3 years ago
A cement factory emits 900 kilograms of CO2 to produce 1,000 kilograms of cement. A fully grown tree removes six kilograms of CO
Dmitriy789 [7]
<h3><u>Answer;</u></h3>

To make the factory carbon neutral, the owners need to grow<em><u> 15000 trees</u></em> over an area of land measuring <em><u>75 acres</u></em>

<h3><u>Explanation and solution;</u></h3>

From the information;

900 kg CO2 = 1000 kg Cement

1 tree = 6 kg CO2

1 acre = 200 trees

<em>100000 kg Cement will require;</em>

<em>=(900 × 100000)/1000</em>

<em>= 90,000 kg of CO2</em>

<em>But 1 tree = 6 kg of CO2</em>

<em>Number of trees = 90,000/6</em>

<em>                            = 15,000 trees </em>

<em>But, 1 acre = 200 trees</em>

<em>Number of acres = 15,000/200</em>

<em>                             = 75 acres of land </em>

Therefore;

To make the factory carbon neutral, the owners need to grow<em><u> 15000 trees</u></em> over an area of land measuring <em><u>75 acres</u></em>

6 0
3 years ago
Read 2 more answers
Emma is working in a shoe test lab measuring the coefficient of friction for tennis shoes on a variety of surfaces. The shoes ar
Rashid [163]

Answer:

Explanation:

Force of friction = μ N , where μ is coefficient of friction , N is normal force on the body .

a )

Given,

Normal force N = 400 N

Force of friction = 300 N

μ = coefficient of static friction = ?

Putting the values ,

300 = 400 μ

μ = .75

b )

Normal force N = 400 N

Force of friction = 200 N

μ = coefficient of kinetic  friction = ?

Putting the values ,

200 = 400 μ

μ = .50

c ) see attached file .

7 0
3 years ago
Scientists earlier believed that the lowest measurable temperature is the freezing point of ice. However, modern scientists beli
djverab [1.8K]
I think the correct answer from the choices listed above is the first option. The statement that best accounts for these different opinions would be that <span>scientists propose contradictory ideas to include all possibilities. Hope this answers the question. Have a nice day.</span>
5 0
3 years ago
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