For this question, we determine first the x and y components of the distances.
3 blocks north:
x - component = +3 ; y-component = 0
4 blocks northeast:
x - component = (cos 45°)(4 blocks) = 2.83 blocks
y - component = (cos 45°)(4 blocks) = 2.83 blocks
5 blocks west:
x-component = -5 ; y-component = 0
Then, we add up all the x-components and all the y-components
x-component (sum) = 0.83
y-component (sum) = 2.83
Then, we determine the magnitude of the block by the equation below.
m = √(x² + y²) = √(0.83² + 2.83²) ≈ 2.95 blocks
Thus, the displacement from the original position is approximately equal to 2.95 blocks.
Explanation:
Given that,
Let ABC is a triangle such that AB is perpendicular distance, BC is base and AC is the hypotenuse of triangle.
Let AB = 210 ft
AC = 90 + x
BC = x
To find :
The dimensions of the cornfield.
Solution :
Pythagoras theorem is used to find the value of x. It is given by :
On solving the above equation we find the value of x, x = 200 ft
So, BC = 200 ft
AC = 90 + 200 = 290 ft
So, the length, base and the hypotenuse of the triangle is 210 ft, 200 ft and 290 ft respectively.
Answer:
Runner A will be 0.05 km from the flagpole, and runner B will be 0.07 km from the flagpole
Explanation:
We can find when their paths will cross as follows:
Where:
is the final position
is the initial position
v₀ is the initial speed
t is the time
a is the acceleration = 0 (since they are running with a constant velocity)
When their paths cross we have:
Now we can find the final distance of each runner.
Therefore, runner A will be 0.05 km from the flagpole, and runner B will be 0.07 km from the flagpole.
I hope it helps you!
Answer:
F1 is equal to F2
Explanation:
Here
F1 is the gravitational force exerted by the earth on the satellite.
F2 is the gravitational force exerted by the satellite on the earth.
Now these two forces are equal but opposite in nature. This is given by the Third law of motion by Newton. According to this law, when there is force exerted between two objects, one force is balanced the other force which is equal in magnitude and opposite in nature.
Thus the gravitational force of the earth exerted on the satellite is equal to the force exerted by the satellite on the earth.
Hence F1 = F2.