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Alex_Xolod [135]
2 years ago
13

Any object that just fits into your visual field has this angular size. Do all objects that you see this this angular size have

the same linear size (the size you would measure by placing a ruler next to them)? If not, when does an object have a larger linear size than another object even though both have the same angular size?
Physics
1 answer:
Nataly_w [17]2 years ago
3 0

Answer:

No the angular and linear size will not be same for different objects bearing the same angular size and is dependent on the point of observation. The greater the distance between the observer and the object, the greater the difference between the angular and linear size.

Explanation:

The angular size is the ratio of two lengths namely

Angular \, Size=\frac{Linear Size}{Distance from the object}

Here if the distance from the object is unity, the angular and linear size will be similar. However if the distance of observation is very large, the angular size for large bodies with large linear size will be very small.

An example in this regard is Sun.

The linear size of Sun, (the diameter) is 1.3927 million km. Which is very large. However as it is very far from earth, 147.44 million km, the angular size is very small.

it is given as

Angular \, Size=\frac{1.39}{147.44}=0.009 rad

Now the same angular size can be of a tennis ball having a diameter of 10 cm , placed at around 10.6 m away.

Angular \, Size=\frac{0.1}{10.6}=0.009 rad

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Answer:

B) The entropy is greater in the second state, with the gas on both sides of the box.

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As we know that ,this is a irreversible process .The process leaves some effect on the surrounding or on the system itself ,is known as irreversible process.But on the other hand those process does not leave any effect on the system and surrounding is known as reversible process.

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3 years ago
cycling at 13.0 m/s on your new aero carbon fiber bike, how much times would it take a pro cyclist to ride in 120 km? Give your
sp2606 [1]

We have that the time in seconds, minutes, and hours is

t=1.083*10^{-4}s

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T_{hours}=3.0083*10^{-8}hours

From the Question we are told that

Velocity v=13.0m/s

Distance d=120 km

Generally the equation for the Time  is mathematically given as

t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s

Therefore

T_{min}=1.083*10^{-4}s/60

T_{min}=1.805*10^{-6}min

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T_{hours}=3.0083*10^{-8}hours

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4 0
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The specific weight of sea water is 10.1 kN/m^3. Convert to lbs/in^3.
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Answer:

0.03719 lbs/in³

Explanation:

Specific weight is given by multiplying the density of an object to the acceleration due to gravity.

\gamma =\rho g\\\Rightarrow \rho=\frac{gamma}{g}\\\Rightarrow \rho=\frac{10.1\times 10^3}{9.81}\\\Rightarrow \rho=1029.562\ kg/m^3

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10.1\ kN/m^3=0.03719\ lbs/in^3

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