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ella [17]
3 years ago
11

Question 6 of 10

Physics
1 answer:
IgorLugansk [536]3 years ago
8 0

C (11.7)

Explanation:

cos 33 ÷ 14 = 11.7

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What is v^2=0.05-4.9 please i need this asap​
Margaret [11]

Answer:

v =2.02

Explanation:

v^2=0.05-4.9

v^2=-4.85

square root both side

v=2.02

^^^^this is a not a perfect square  

7 0
3 years ago
How many neutrons are in an atom of Carbon-13 or (613C)?
vivado [14]

Answer: 6 OR 7

Explanation:

3 0
3 years ago
What is the Validity measures of a basketball bouncing
kykrilka [37]

This study was aimed at testing the construct validity of the basketball basic motion skills test instrument (ITK GDBB). The research used descriptive method of 3 basketball experts in the city of Cimahi; 3 experts are the expert in basketball. The instrument used was the ITB GDBB developed by Silvy (2019) consisting of top passing, bottom passing, top service, bottom service, chest passing, bounding passing, overhead passing, and leading ball (dribbling). This instrument consists of 76 items that cover 4 domains in basketball, namely chest pass, overhead pass, bound pass, and dribbling. The validity method used the construct validity of different power types. For the reliability method, it used the Kuder Ricardson (KR) and Objectivity analysis. The results of the construct validity analysis of a total of 76 items show that the score is ranged from 0.67 to 1.00. The construct validity value of 71 items in the basketball game is in the high category (= 1.00), 5 items are in the sufficient category, the relativity score is ranged from 0.75 to 0.98, and the objectivity score is ranged from 0.89 to 0.95. The conclusion is that this test instrument can be used as a standardized basic motion skill test for standardized large ball games for validity in basic motion skills in basketball games for grade VII junior high school students.

3 0
3 years ago
A particle of mass 2 g travel a distance of 12 m in a time travel of 2 minute assuming the speed was constant find its kinetic e
balandron [24]

Answer:

0.00001 J

Explanation:

k.e =  \frac{1}{2} m {v}^{2}  \\  =  \frac{1}{2} (0.002) { ( \frac{12}{120} )} ^{2}  \\  = 0.00001j

3 0
3 years ago
A playground merry-go-round spins about its axis with negligible friction. A child moves from the center of the merry-go-round t
Juli2301 [7.4K]

Answer:

B

Explanation:

In this process on merry go round there is not any external torque so angular momentum will be conserve. Mass is always conserved.

4 0
3 years ago
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