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3 years ago

Why does pumping more air into a basketball increse the pressure inside the ball?

1 answer:

8 0

Think of it as a balloon when you pump air into it it grows bigger but, if you put too much air into it what happens it pops because the pressure was too much for the balloon to withhold. That's the same with a basketball when you pump air into it the pressure pushing on the material increases.

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J.J. Thomson's model of the atom includes all BUT ONE of these features. That is

kakasveta [241]

Answer:

Explanation:

usa testprep!!!!!

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3 years ago

Calculate the solubility of zn(oh)2(s) in 2.0 m naoh solution. (hint: you must take into account the formation of zn(oh)2−4, whi

Brilliant_brown [7]

When we have:

Zn(OH)2 → Zn2+ 2OH- with Ksp = 3 x 10 ^-16

and:

Zn2+ + 4OH- → Zn(OH)4 2- with Kf = 2 x 10^15

by mixing those equations together:

Zn(OH)2 + 2OH- → Zn(OH)4 2- with K = Kf *Ksp = 3 x 10^-16 * 2x10^15 =0.6

by using ICE table:

Zn(OH)2 + 2OH- → Zn(OH)4 2-

initial 2m 0

change -2X +X

Equ 2-2X X

when we assume that the solubility is X

and when K = [Zn(OH)4 2-] / [OH-]^2

0.6 = X / (2-2X)^2 by solving this equation for X

∴ X = 0.53 m

∴ the solubility of Zn(OH)2 = 0.53 M

4 0

3 years ago

What is the purpose of finding oxidation states in the half-reaction method for balancing equations?

vazorg [7]

Answer:

B. To Identify the half reactions for the equation

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3 years ago

A sub-shell with n = 6, l = 2 can accommodate a maximum of:

Mrrafil [7]

Answer:

Explanation:

2n^2

n=6

2(6)^2=2×36

=72

8 0

3 years ago

a sample of 3.00 g of so2 (g)originally in a 5.00 L vesselat 21 degee Celsius is transferred to a 10.0 L vessel at 26 degree Cel

eimsori [14]

Answer:

1) The partial pressure of SO₂ gas in the larger container = 0.115 atm.

2) The partial pressure of N₂ gas in the larger container = 0.206 atm.

3) The total pressure in the vessel = 0.321 atm.

Explanation:

To calculate the partial pressure of each gas, we can use the general law of ideal gas: PV = nRT.

where, P is the partial pressure of the gas in atm,

V is the volume of the vessel in L,

n is the no. of moles of the gas,

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas in K.

1) What is the partial pressure of SO₂ gas in the larger container?

∵ P = nRT/V.

n = mass/molar mass = (3.0 g)/(64.066 g/mol) = 0.047 mol.

R = 0.082 L.atm/mol.K.

T = 26 °C + 273.15 = 299.15 K.

V = 10.0 L. (The volume of the new container)

∴ P = nRT/V = (0.047 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.115 atm.

2) What is the partial pressure of N₂ gas in the larger container?

∵ P = nRT/V.

n = mass/molar mass = (2.35 g)/(28.0 g/mol) = 0.084 mol.

R = 0.082 L.atm/mol.K.

T = 26 °C + 273.15 = 299.15 K.

V = 10.0 L. (The volume of the new container)

∴ P = nRT/V = (0.084 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.206 atm.

3) What is the total pressure in the vessel?

According to Dalton's law the total pressure exerted is equal to the sum of the partial pressures of the individual gases.

∵ The total pressure in the vessel = the partial pressure of SO₂ + the partial pressure of N₂.

∴ The total pressure in the vessel = 0.115 + 0.206 = 0.321 atm.

5 0

3 years ago