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konstantin123 [22]
2 years ago
15

A compound is 39.97% carbon, 13.41% hydrogen, and 46.62% nitrogen. What is the empirical formula?

Chemistry
2 answers:
FromTheMoon [43]2 years ago
7 0

Answer: CH4N is correct

Explanation:

39.97% carbon

13.41% hydrogen

46.62% nitrogen.

inessss [21]2 years ago
3 0

Answer:

CH4N

A compound is 39.97% carbon, 13.41% hydrogen, and 46.62% nitrogen.

Explanation:

Hope this helps.

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A sample of pure oxalic acid (H2C2O4.2H2O) weighs 0.2000 g and requires 30.12 ml of KOH solution for
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 The molarity  of KOH  is  0.1055 M

 <u><em> calculation</em></u>

Step  1: write  the  equation  for reaction between H₂C₂O₄.2H₂O  and KOH

H₂C₂O₄.2H₂O  + 2 KOH   →    K₂C₂O₄ +4 H₂O

step 2: find the moles  of H₂C₂O₄.2H₂O

moles = mass÷ molar  mass

from  periodic  table the  molar mass H₂C₂O₄.2H₂O= (1 x2) +(12 x2) +(16 x4)  + 2(18)=126 g/mol

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step 3: use the  mole  ratio  to  calculate the moles of KOH

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therefore the  moles of KOH  =0.00159 x 2 = 0.00318  moles

step 4: find molarity of KOH

molarity = moles/volume in liters

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