The answer to the question is a
<h3><u>Answer;</u></h3>
0.180 moles of HgO
<h3><u>Explanation;</u></h3>
The atomic weight of mercury is 200.5
The atomic weight of oxygen is 16.0
Therefore; the molecular weight (per mole) of mercury oxide is 216.5 g
Hence;
Number of moles = 39 g/(216.5 g/mole)
= 0.180 moles of HgO.
2H2 +O2 ----> H2O
The primary product is water.
Answer:

Explanation:
The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

C(s) + H₂O(g) ⇌ CO(g) + H₂(g)
ΔH°f/kJ·mol⁻¹: 0 -241.8 -110.5 0
