In an acid/base titration where NaOH(aq) is the titrant and HCl(aq) is the analyte, what is true about the moles of each reactan
1 answer:
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Explanation:
Molarity is defined as number of moles per liter of solution.
Mathematically, molarity =
It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.
molarity =
0.0800 M =
no. of moles = 1.6 mol
Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.
No. of moles =
mass in grams =
=
= 399.488 g
Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.
Explanation:
The number acquired by an element after the lose or gain of an electron is called oxidation number.
For example,
Here, oxidation number of Fe(s) is 0 and Fe in is +3.
Oxidation number of O in is 0 as it is present in its elemental state.
The oxidation number of O in is calculated as follows.
Hence, oxidation number of O in is -2.
- The loss of electrons by an element or substance is called oxidation. Here, electrons are being lost by Fe(s) as an increase in oxidation state is occurring. So, Fe(s) is oxidized.
- The gain of electrons by an element or substance is called reduction. Here, electrons are being added to
as a decrease in its oxidation state is occurring. So,
- An element or compound which is being reduced is called oxidizing agent. Here,
- An element or compound which is being oxidized is called reducing agent. Here, Fe(s) is the reducing agent.