The equation of a straight like in the from y – y1 =m(x-x1) where m is the slope of the like and (x1 , y1) are the coordinates of a given point on the line — compare slope intercept form.
Answer:
Is the graph shown the initial triangle, or the translated one?
Step-by-step explanation:
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)
The equation of the given line is
7x+4y=3
4y = - 7x + 3
y = -7x/4 + 3/4
Comparing with the slope intercept form, slope = -7/4
If the line passing through the given point is perpendicular to the given line, it means that its slope is the negative reciprocal of the slope of the given line.
Therefore, the slope of the line passing through (6,-9) is 4/7
To determine the intercept, we would substitute m = 4/7, x = 6 and y = -9 into y = mx + c. It becomes
- 9 = 4/7×6 + c = 24/7 + c
c = - 9 - 24/7 = -87/7
The equation becomes
y = 4x/7 - 87/7
Answer:
This is what internet says. Maybe this helps.
