Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
It is that’s wat I got 1028
9514 1404 393
Answer:
3, 0, 2, -2
Step-by-step explanation:
Put x=2 into each equation and solve for y.
<u>2 + y = 5</u>
y = 5 -2
y = 3
<u>3x +2y = 6</u>
3·2 +2y = 6
2y = 6 -6 = 0
y = 0
<u>2x +y = 6</u>
2·2 +y = 6
y = 6 -4
y = 2
<u>5x +3y = 4</u>
5·2 +3y = 4
3y = 4 -10 = -6
y = -2
Answer:
hello there,
the answer for this equation is:
The value of Start Fraction 6 Over x End Fraction + 2x2, when x = 3 is 20.
Step-by-step explanation:
:
Y is the function of x so there are two things called Input and output
