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Pachacha [2.7K]
3 years ago
7

Choose the answers that describe an example of acceleration.

Physics
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

should be B

Explanation:

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If Ike notices that there is a new moon tonight, when should he expect there to be a new moon again?
podryga [215]
Whatever phase of the moon Ike sees, he can expect to see
the same phase of moon again, after 29.53 days later.
5 0
3 years ago
A person travels from New York to Washington at the rate of 45 km per hour and
mr_godi [17]

Answer:

The average speed for the whole journey is 49.5 miles per hour.

Explanation:

Step 1 :

Here, both the ways, he covers the same distance.  Then, the formula to find average speed is

=  2xy / (x+y)

Step 2 :

x ----> Rate at which he travels from New York to Washington  

x  =  45

y ----> Rate at which he travels from New York to Washington  

y  =  55

Step 3 :

So, the average speed is

=  (2 ⋅ 45 ⋅ 55) / (45 + 55)

=  4950 / 100

=  49.5

8 0
3 years ago
1. How will the ice water mix with the salty water? Write your hypothesis below.
andrew11 [14]
It won't be able to mix because one will not get evaporated and it wont go together
6 0
3 years ago
\Which are consumers within a spruce-fir forest ecosystem?
lara [203]

The answer is mushroom.

6 0
3 years ago
Read 2 more answers
Một mặt phẳng vô hạn tích điện đều, mật độ σ = 4.10-9 C/cm2, đặt thẳng đứng trong không khí. Một quả cầu nhỏ có khối lượng 8 g,
dusya [7]

Answer:

The angle is 18.3 degree.

Explanation:

A uniformly charged infinite plane, density σ = 4 x 10^-9 C/cm^2, is placed vertically in air. A small ball of mass 8 g, with charge q = 10^-8 C, hangs close to the plane, so that the string is initially parallel to the plane. Take g = 9.8m/s2. When in equilibrium, by what angle is the string hanging the ball to the plane?

surface charge density, σ = 4 x 10^-5 C/m^2

Charge, q = 10^-8 C

mass, m = 0.008 kg

Let the angle is A and the tension in the string is T.

The electric field due to a plane is

E =\frac{\varepsilon \sigma }{2\varepsilon o}\\\\E =\frac{4\times 10^{-5}}{2\times 8.85\times 10^{-12}}\\\\E = 2.26\times 10^6 V/m \\

Now equate the forces,

T sin A = q E.... (1)\\\\T cos A = m g ..... (2)\\\\divide (1) by (2)\\\\tan A = \frac{10^{-8}\times 2.6\times 10^6}{0.008\times 9.8}\\\\tan A = 0.33\\\\ A = 18.3 degree

5 0
3 years ago
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