The answer here would be infrared waves. Hot objects and humans give off heat in the form of infrared light, thermal imaging technology in the goggles enable them to catch this light emitted by these objects
Answer and Explanation:
the electronic devices always have some noises present in the signal
there are some important considerations in optical fiber communications these are.
- the noise which is contributed by transmitter are electronic random noise, low frequency noise
- noise which is contributed by laser are relative intensity noise, mode partition noise, conversion of phase noise to amplitude noise.
- noise contributed by photo detector are quantum shot noise, shot noise from dark current, avalanche multiplication noise.
PRINCIPLE OF POPULATION INVERSION :
The principle of population inversion is defined as for production of high percentage of simulated emission for a laser beam the number of atoms in higher state should be greater than lower energy state
Answer:
the answer is
Explanation:
constant acceleration
because when the object's velocity is changing then the object is accelerating or decelerating
as acceleration describe changing of velocity so the answer is constant acceleration
Acceleration is defined as the rate of change of velocity.
Acceleration = (Change in velocity) / time taken
Acceleration = (Final velocity - initial velocity) / time
As the object velocity changes by the same amount in each second, it means the acceleration is constant.
Hope I can help u
Answer:
C True. they rise and fall in a circular motion
Explanation:
The movement of water waves in the sea is described by a simple harmonic movement where the water droplets, which are the material particles of the movement oscillate up and down and the wave that is the energy of the movement travels perpendicular to it.
With this let's review the claims
A False
B False
C True.
D False
Answer:
A) 
B) 
C) 
D) mosquitoes speed in part B is very much larger than that of part C.
Explanation:
Given:
- Distance form the sound source,

- sound intensity level at the given location,

- diameter of the eardrum membrane in humans,

- We have the minimum detectable intensity to the human ears,

(A)
<u>Now the intensity of the sound at the given location is related mathematically as:</u>
..........................................(1)



<em>As we know :</em>


is the energy transferred to the eardrums per second.
(B)
mass of mosquito, 
<u>Now the velocity of mosquito for the same kinetic energy:</u>



(C)
Given:
- Sound intensity,

<u>Using eq. (1)</u>



Now, power:



Hence:




(D)
mosquitoes speed in part B is very much larger than that of part C.