Question

Help with 4 and 5 and also the one below... I WILL GIVE BRAINLIEST TO THE CORRECT ANSWER!

Answer 1

Answer: does anyone have the answers to the sound and hearing quiz unit 6 lesson 1 I need them ASAP

Answer 2

#1

as per the formula of level of sounds we know that

$L = 10 Log\frac{I}{I_o}$

now for two different levels we can use that

$L_2 - L_1 = 10 Log\frac{I_2}{I_1}$

now plug in data in above equation

$50 - 20 = 10 Log \frac{I_2}{I_1}$

$10^3 = \frac{I_2}{I_1}$

now we know that

$\frac{I_2}{I_1} = \frac{r_1^2}{r_2^2}$

$10^3 = \frac{15^2}{r^2}$

$r = 47 cm$

#4)

level of sound is given as 110 dB

now we can say

$L = 10 Log\frac{I}{I_0}$

$110 = 10 Log\frac{I}{10^{-12}}$

$I = 0.10 W/m^2$

now the energy received per second is given as

$P = Intensity \times area$

$P = 0.10 \times \pi r^2$

$P = 0.10 \times \pi(0.003)^2$

$P = 2.8 \mu J$

#5

length of the canal is 2.4 cm

resonating frequency of first harmonic is given as

$f = \frac{v}{4L}$

$f = \frac{340}{4\times 0.024}$

$f = 3.6 kHz$