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LekaFEV [45]
3 years ago
8

What is the relationship between the 6’s in 660,472

Mathematics
1 answer:
belka [17]3 years ago
6 0

well, the 6 in the ten thousands place is 10 times left then the 6 in the hundred thousands place as well as the 6 in the hundred thousand place is 10 times more then the 6 in the ten thousands place.

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Are the graphs of −5y=2x+3 and y=25x+4 parallel, perpendicular, or neither?
saw5 [17]
Parallel graphs have the same slope. perpendicular has opposite reciprocal slopes. These equations have slopes of -2/5 and 25 so they are neither.
6 0
3 years ago
What needs to be corrected in this construction of a line parallel to AB passing through C?
monitta

Answer;

C) The second arc should be centered at C.

Explanation;

Assuming the goal is to construct a line parallel to AB that passes through given point C.

-Draw a line through C and across AB at an angle creating D.

- With the compass width about half of DC, and center D, draw the first arc to cross both lines.

-Using the same compass width , draw the second arc with center C.

-Then set the compass width to the lower arc (the first arc)

- Move the compass to the second arc. Mark off an arc to make point E

-Draw a straight line through C and E

Thus the line CE will be parallel to line AB

3 0
3 years ago
Read 2 more answers
Math help.... Please....
garri49 [273]
First, you want to solve for the equation for this problem, would be: 
0.05N + 0.10D = 20.50 
While N = The amount of nickels, and D = The amount of dimes. 

Since N = 164, and D = 123. It would add up to 287 coins. 164 + 123 = 287. 
Now that you have the number for those two variables, solve the equation for when N = 164, and D = 123. 
0.05N + 0.10D = 20.50 
<span>0.05(164) + 0.10(123) = 20.50 
</span><span>8.2 + 12.3 = 20.50 
</span>20.50 = 20.50 
So, there is 164 nickels, and 123 dimes for your answer. 

<em>I hope this helps! </em>

<em>~ Notorious Sovereign</em>
6 0
3 years ago
Read 2 more answers
Which graph shows the solutions to<br> the inequality? PLSSS HELPPP
gavmur [86]
It’s the third graph down!!
7 0
3 years ago
a standard deck of cards missing the queen of hearts in the 2 of clubs what is the probability of pulling either an ace or a spa
Butoxors [25]
<h3>Answer:  8/25</h3>

=======================================================

Explanation:

In a standard deck, there are 52 cards.

If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.

There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.

Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.

-----------------

The event space has A = 16 cards in it, while the sample space has B = 50 cards.

The probability we're after is A/B = 16/50 = 8/25

5 0
2 years ago
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