What is the relationship between the 6’s in 660,472

1 answer:

6 0

well, the 6 in the ten thousands place is 10 times left then the 6 in the hundred thousands place as well as the 6 in the hundred thousand place is 10 times more then the 6 in the ten thousands place.

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Please help!!! I just need a simple explanation I will mark brainliest!

aniked [119]

Answer:

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6 0

2 years ago

Select all that apply. Which of the following are proportions? 25/10=5/2,3/4=8/10,2/8=3/12,3/4=15/20

8_murik_8 [283]

Answer:

$\frac{25}{10} = \frac{5}{2}$ is in proportion.

$\frac{3}{4} = \frac{8}{10}$ is not in proportion.

$\frac{2}{8} = \frac{3}{12}$ is in proportion.

$\frac{3}{4} = \frac{15}{20}$ is in proportion.

Step-by-step explanation:

The first example is $\frac{25}{10} = \frac{5}{2}$ and it is in proportion.

This is because, you will get the same simplest fraction ( $\frac{5}{2}$ ) from the fraction $\frac{25}{10}$ by dividing its numerator and denominator by 5.

The second example is $\frac{3}{4} = \frac{8}{10}$ and it is not in proportion.

This is because, you can not get the simplest fraction ( $\frac{3}{4}$ ) from the fraction $\frac{8}{10}$ after simplification.

The third example is $\frac{2}{8} = \frac{3}{12}$ and it is in proportion.

This is because, you will get the same simplest fraction ( $\frac{1}{4}$ ) from the fraction $\frac{2}{8}$ by dividing its numerator and denominator by 2 and from the fraction $\frac{3}{12}$ by dividing its numerator and denominator by 3.

The fourth example is $\frac{3}{4} = \frac{15}{20}$ and it is in proportion.

This is because, you will get the same simplest fraction ( $\frac{3}{4}$ ) from the fraction $\frac{15}{20}$ by dividing its numerator and denominator by 5. (Answer)

3 0

2 years ago

Read 2 more answers

$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent

photoshop1234 [79]

$\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\
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\text{we know that the amount after t year when compounded is given by}\\
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A=P\left ( 1+\frac{r}{n} \right )^{nt}\\
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\text{here P is the principal amoount, so }P=7000,\\
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\text{r is the interest rate, }r=11\%=0.11\\
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\text{n is the number of times in a year, here semiannulay, so }n=2,\\
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\text{and t is the time, so }t=21\\
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\text{so the amount after 21 years is}$

$A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\
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\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\
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\Rightarrow A=7000\left ( 1.055 \right )^{42}\\
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\Rightarrow A\approx 66328.68$