<span>It looks like I could substitute the x=2y-1. Into 2x+y=3
2(2y-1)+y=3
4y-2+y=3
5y=5
y=1
x=2(1)-1
x=1
</span><span> (1,1)
CHECK
2x+y=3
2(1)+(1)=3
2+1=3
3=3
Left hand side=Right hand side
Check other equation
x=2y-1
1=2(1)-1
1=1
</span><span>Therefore the solution is (1,1). Since the left hand side= right hand side in each equation</span>
For this you would use Pythagorean theorem (a^2+b^2=c^2) a=15 and c=sqrt 514 plug the numbers in and you’ll be set
Answer:
the magnitude is 7
Step-by-step explanation:
as i means unit vector along x-axis so the magnitude of i is 1 and now,
= 12 - 5×1
= 12- 5
= 7
There is no picture to look at
The answer is 86
Following PEMDAS, which is:
parentheses
exponents
multiplication
division
addition
subtraction
I found that the answer was 86
