Answer:
H'(15, - 7)
Step-by-step explanation:
Given the translation < 10, - 11 >
Add 10 units to the x- coordinate of H and subtract 11 units from the y- coordinate of H, that is
H(5, 4) → H'(5 + 10, 4 - 11) → H'(15, - 7)
Answer:
a) How much work has he done = dW = 1.3 × 105 J
b) What is the magnitude of the heat that he has lost = dQ = -5.4 × 105 J
Step-by-step explanation:
- From the first law of thermodynamics; dQ = dU + dW
Hence, work done dW = dQ - dU
dW = -6.7 × 105 J - ( -8.0 × 105 J)
dW = 1.3 × 105 J is the work done by the player
- for heat lost; from dQ = dW + dU
- dU = -8.0 × 105 J and dW = 2.6 × 105 J
- heat lost dQ = 2.6 × 105 J + ( -8.0 × 105 J)
- The negative is as a result of heat lost by the player
If the question is Log4 (8/x)^2
Then...
Log^2 2^2 (8/x)
(1/2 Log2 (8/x))^2
1/4 Log^2 2(8/x)
(log^2 2(8/x))/4
(9-6log2 (x)+ log^2 2(x))/4
Answer:
C. 20%
Step-by-step explanation:
50*2=100
40*2=80
100-80=20
