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3 years ago

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A hot piece of metal is placed in an airtight chamber. The metal radiates heat to the surrounding air. Which of the following wo

uld increase the amount of heat the metal radiates to the air? A. decreasing the metal's temperature B. increasing the amount of air in the chamber C. decreasing the amount of air in the chamber D. increasing the metal's temperature

2 answers:

Alina [70]3 years ago

4 0

Answer:

<u>D</u>

Step-by-step explanation:

Serga [27]3 years ago

3 0

D. Increasing the metal’s temperature

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If anyone can please help me

MA_775_DIABLO [31]

Answer:

1/4

Step-by-step explanation:

5 orange + 5 mango = 10

P( mango ) = mango /total = 5/10 = 1/2

Replace

5 orange + 5 mango = 10

P(orange ) = orange /total = 5/10 = 1/2

P(mange, replace, orange) = 1/2 * 1/2 = 1/4

4 0

3 years ago

Find the sum of the following infinite geometric series.

Crazy boy [7]

Answer:

Final answer is $\frac{80}{3}$ .

Step-by-step explanation:

We have been given an infinite geometric series.

Now we need to find it's sum.

common ratio $r=-\frac{1}{5}$ .

plug n=1 to get the first term

$a_n=32\left(-\frac{1}{5}\right)^{\left(n-1\right)}$

$a_1=32\left(-\frac{1}{5}\right)^{\left(1-1\right)}$

$a_1=32\left(-\frac{1}{5}\right)^{\left(0\right)}$

$a_1=32\left(1\right)$

$a_1=32$

Now plug these values into infinite sum formula

$S_{\infty}=\frac{a_1}{1-r}=\frac{32}{1-\left(-\frac{1}{5}\right)}=\frac{32}{1.2}=\frac{320}{12}=\frac{80}{3}$

Hence final answer is $\frac{80}{3}$ .

8 0

2 years ago

Transformation!! Please only help if you have the answer!!

pshichka [43]

Answer:

the answer for this one is A

Step-by-step explanation:

mostly because for this you're only looking for H and not the rest of them so if you reflect is itll be in the same spot just on the opposite side

8 0

3 years ago

Simplify the monomials

Zielflug [23.3K]

Answer:

$(4a)^{-3}*^{-4}$

$x^m*x^n=x^{m+n}$

$(4a)^{-3}*a^{-4}$

$(-4)^{-3}\: a^{-3}*a^{-4}$

$4^{-3}\:a^{-3-4}$

$\cfrac{1}{4^3} \:a^{-7}$

$\boxed{\frac{1}{64a^{7}} }$

~

$(3xy)^2*(-4x^3y^2)^3$

$9x^2y^2*(64x^9y^6)$

$\boxed{-576x^{11}y^8}$

~

$(4a^{-1}b^5c^{-3})^3$

$(4)^3(a^{-1})^3(b^5)^3(c^{-3})^3$

$(4*4*4)\:a^{-1*3}\:b^{5*3}\:c^{-3*3}$

$64\:a^{-3}b^{15}c^{-9}$

$\boxed{\frac{64b^{15}}{a^3c^9}}$

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2 years ago

What is the median of the data below?

ExtremeBDS [4]

I think it is 35. i hope i have helped you

5 0

2 years ago

Read 2 more answers