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Wittaler [7]
3 years ago
9

The fuel efficiency of one type of car is recorded in a scatterplot where the amount of gas used, x (in gallons), is paired with

the distance traveled, y (in miles), for various trips. The equation for the line of best fit for the data is y = 28x. How can the y-intercept and slope of this line be interpreted?
The y-intercept is 28, which represents the miles that can be traveled with 1 gallon of gas. The slope is 0, which represents the amount of gas used when 0 miles are traveled.
The y-intercept is 28, which represents the amount of gas used when 0 miles are traveled. The slope is 0, which represents the miles that can be traveled with 1 gallon of gas.
The y-intercept is 0, which represents the number of miles that can be traveled with 1 gallon of gas. The slope is 28, which represents the amount of gas used when 0 miles are traveled.
The y-intercept is 0, which represents the amount of gas used when 0 miles are traveled. The slope is 28, which represents the miles that can be traveled with 1 gallon of gas.
Mathematics
2 answers:
Musya8 [376]3 years ago
6 0

Answer:

D on edg

Step-by-step explanation:

sukhopar [10]3 years ago
4 0

Answer:

The y-intercept is 0, which represents the amount of gas used when 0 miles are traveled. The slope is 28, which represents the miles that can be traveled with 1 gallon of gas

Step-by-step explanation:

Let

x----> the amount of gas used in gallons

y ---> the distance traveled in miles

we have

y=28x

This linear equation represent a direct variation

The y-intercept is the value of y when the value of x is equal to zero

For x=0, y=0

That means ----> The y-intercept is 0, which represents the amount of gas used when 0 miles are traveled

The slope is m=28\ \frac{miles}{gallon}

That means ----> The slope is 28, which represents the miles that can be traveled with 1 gallon of gas

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Silvia hiked a 30-mile trail in 3 days. The first day, she hiked 50% of the total distance. The second day, she hiked 25% of the
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A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv
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Answer:

Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

            of  novels that seniors read during their time in college. An exit

            survey was conducted with a random sample of 9 seniors. The

            sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

              been met, which of the following is a 94.645% confidence

              interval for the population mean number of novels read by

              all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

                                = n - 1

                                = 9 - 1

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⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

   =1 - 0.94645

  =0.05355 ≈ 0.05

⇒α = 0.5

Now,

\frac{\alpha}{2} = \frac{0.05}{2}

  = 0.025

Then,

t_{\frac{\alpha}{2}, df }  = 2.306

∴ we get

Population mean = x⁻ ± t_{\frac{\alpha}{2}, df } ×\frac{s}{\sqrt{n} }

                           = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

⇒Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

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